Answer:
$1.50
Step-by-step explanation:
Let cheese pizza be C and mushroom pizza be M
Given 3C+2B+4M+=+12.50
and
3C+2B+2M=8.50
Using elimination
3C+2B+4+=12.50
3C+2B+2M=8.50
------------------------ subtract the second equation from the first one to get
2M=4.00
Solve for M
M+=+2.00 mushroom slice costs $2 each
Using that info, substitute for M in either equation to find C
3C+2B+2M=8.50
3C+2B+22A2=8.50
3C+2B+4=8.50
3C=4.50
C+=1.50
Is there a photo? So I can help
Answer:
f(x)=60[1/3]^x
initial value⇒ x=0, f(x) = 60*[1/3]^0 = 60*1 = 60
x=1 ⇒f(1) = 60*[1/3]
x=2 ⇒f(2) = 60*[1/3]^2 = f(1) * [1/3]
x = n ⇒ f(n) = 60*[1/3]^n=60*[1/3]^(n-1)*[1/3] = f(n-1)*[1/3]
Then, the right choice is: the graph has an initial value of 60, and each successive term is determined by multiplying by 1/3
Step-by-step explanation:
i think this is what your looking for
Answer:
4x degrees= 52 degrees
(2x+12) degrees= 38 degrees
Step-by-step explanation:
4(13)=52
(2(13)+12)=38
The first thing you need to do is say that <span>x = 3sec(u) ==> dx = 3sec(u)tan(u) du
If we say this we can proceed in this manner
</span>∫ 1/[x^2√(x^2 - 9)] dx
<span>= ∫ 3sec(u)tan(u)/{9sec^2(u)√[9sec^2(u) - 9]} du, by applying substitutions </span>
<span>= ∫ 3sec(u)tan(u)/{27sec^2(u)tan(u)] du, since tan^2(u) = sec^2(u) - 1 </span>
<span>= 1/9 ∫ 1/sec(u) du, by canceling sec(u)tan(u) du </span>
<span>= 1/9 ∫ cos(u) du, since 1/sec(u) = cos(u) </span>
<span>= (1/9)sin(u) + C. </span>
<span>With x = 3sec(u) ==> sec(u) = x/3 and cos(u) = 3/x, we have: </span>
<span>sin(u) = √[1 - cos^2(u)] = √[1 - (3/x)^2] = √(x^2 - 9)/x. </span>
<span>Therefore, back-substituting yields: </span>
<span>∫ 1/[x^2√(x^2 - 9)] dx = (1/9)sin(u) + C </span>
<span>= (1/9)[√(x^2 - 9)/x] + C </span>
<span>= √(x^2 - 9)/(9x) + C.
</span>The answer will be: <span>sqrt(x^9-9)/9x
I hope this helps a lot </span>
