The derivative of the function g(x) as given in the task content by virtue of the Fundamental theorem of calculus is; g'(x) = √2 ln(t) dt = 1.
<h3>What is the derivative of the function g(x) by virtue of the Fundamental theorem of calculus as given in the task content?</h3>
g(x) = Integral; √2 ln(t) dt (with the upper and lower limits e^x and 1 respectively).
Since, it follows from the Fundamental theorem of calculus that given an integral where;
Now, g(x) = Integral f(t) dt with limits a and x, it follows that the differential of g(x);
g'(x) = f(x).
Consequently, the function g'(x) which is to be evaluated in this scenario can be determined as:
g'(x) =
= 1
The derivative of the function g(x) as given in the task content by virtue of the Fundamental theorem of calculus is; g'(x) = √2 ln(t) dt = 1.
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Answer:
here you go :)
Quadrant lll is always both negative so the answer is (-1/2, -1/4)
Step-by-step explanation:
Answer:
x = -3
Step-by-step explanation:
The 4th one is the answer
Answer:
$625
Step-by-step explanation:
If Todd has to pay $14,000 in tuition for his school each year and uses $6,500 in financial aid each year all for 2 years, the money he needs to save can be modeled by:
2(-$14000 + $6500) + 2(12x) = 0.
x is the minimum amount of money he needs to save in order to cover this expense without debt.
Thus 2(-$14000 + $6500) + 2(12x) = 0 →
2(-$7500) + 24x = 0 → -$15000 + 24x = 0 →
24x = $15000 → x = $625