Find the derivative of
f(x)=(arccost)second power
1 answer:
1 - Derivative of arcsin x.
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The derivative of f(x) = arcsin x is given by
</span><span> f '(x) = 1 / sqrt(1 - x 2) </span><span>
</span>2 - Derivative of arccos x.
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The derivative of f(x) = arccos x is given by
</span><span> f '(x) = - 1 / sqrt(1 - x 2) </span><span>
</span>3 - Derivative of arctan x.
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The derivative of f(x) = arctan x is given by
</span><span> f '(x) = 1 / (1 + x 2) </span><span>
</span>4 - Derivative of arccot x.
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The derivative of f(x) = arccot x is given by
</span><span> f '(x) = - 1 / (1 + x 2) </span><span>
</span>5 - Derivative of arcsec x.
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The derivative of f(x) = arcsec x tan x is given by
</span><span> f '(x) = 1 / (x sqrt(x 2 - 1))</span><span>
</span>6 - Derivative of arccsc x.
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The derivative of f(x) = arccsc x is given by
</span><span> f '(x) = - 1 / (x sqrt(x 2 - 1)) </span><span>
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Answer:
isosceles
x=14
Step-by-step explanation:
isosceles because of the two I symbols on the triangle
x+5=2x-9
5+9=2x-x
14=x
Answer:
0.18
Step-by-step explanation:
C is a subpath of A,
first P(A) = 0.6 since the line leading to A says .6
the probability of choosing C is 0.3, but first we have to assume A is chosen. The true probability is 0.3 * 0.6 = 0.18
It would be 13 because you are adding 5 and 8
-3(-x)-6=-3x+10
-3 -3
(-x)-6=-3x+7
-6 -6
(-x)=-3x+1
i only got this far!! im so sorry!!
Using the midpoint formula we get:
(x,y)=(0+5/2, 0+12/2) or (5/2, 6) as the midpoint.
