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allochka39001 [22]
3 years ago
11

If a player rolls 2 dice and gets a sum of 2 or 12, he wins $30. If the person gets a 7, he wins $10. Otherwise he wins nothing.

If the cost to play the game is $3, what does a player expect to get out of this game every time he/she plays?
Mathematics
1 answer:
makkiz [27]3 years ago
7 0

If they were to win $30 they would expect to get $27 in profit.

If they were to win $10 they would expect $7.

If they were to win $0 they would expect $-3 in profit, so technically if they win nothing they lose money.

Hope I could help! :D

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Plz help and I will give brainliest
DiKsa [7]

Answer:

a. f<g is one of them. On the number line, g is closest to 0, meaning it is greater than f.

b. h>0 is one answer. H is to the right of 0, meaning that h is greater than 0.

c. im sorry, i dont know.

Step-by-step explanation:

If this is graded, I hope you get a good grade!

4 0
3 years ago
70% of the world's snake species lay eggs, while the remaining ones give birth to live young. If there are 2,700 different speci
igomit [66]
If 70% lay eggs, that leaves the remaining 30% to give live birth. 2700(0.30) = 810 species
8 0
3 years ago
I need to know what X= for all of these please<br><br> Worth 15 points
olga2289 [7]

Answer:

i answered this so you can give the other person brainliest

Step-by-step explanation:

8 0
3 years ago
Suppose that prices of recently sold homes in one neighborhood have a mean of $265,000 with a standard deviation of $9300. Using
Hatshy [7]

Answer:

Range  = (237100, 292900)

Step-by-step explanation:

Using Chebyshevs Inequality:

P(|X - \mu | \le k \sigma )\ge 1  -\dfrac{1}{k^2}= 0.889

1  -\dfrac{1}{k^2}= 0.889

\dfrac{1}{k^2}= 1- 0.889

\dfrac{1}{k^2}=0.111

k = \sqrt{\dfrac{1}{0.111}}

k \simeq 3

Thus, 88.9% of the population is within 3 standard deviation of the mean with the Range = μ  ±  kσ

where;

μ = 265000

σ = 9300

Range = 265000  ±  3(9300)

Range = 265000  ± 27900

Range =   (265000 - 27900, 265000 + 27900)

Range  = (237100, 292900)

3 0
2 years ago
adam wants to compare the fractions 3/12,1/6, and 1/3.he wants to order them from least to greatest and rewrite them so they all
Digiron [165]
3/12 ; 1/6 ; 1/3

Adam must first get the least common multiple of each denominator.

12 : 12, 24, 36
  6 :  6, 12, 18
  3 :  3, 6, 9, 12

12 is the least common denominator. 

We, then, multiply each denominator by a number that will produce 12.

12 x 1 = 12
6 x 2 = 12
3 x 4 = 12

Each number multiplied to the denominator must be the number used to multiply each numerator.

3/12 * 1/1 = 3/12
1/6 * 2/2 =   2/12
1/3 * 4/4 =   4/12

Since they now share a common denominator, the numerator will become the basis of the fraction's value. The greater the numerator, the greater the fraction's value.

Fractions in order from least to greatest = 2/12 ; 3/12 ; 4/12

Substitute each fraction with its original fraction:
2/12 ⇒ 1/6   : least

3/12 ⇒ 3/12 : middle
4/12 ⇒ 1/3   : greatest
7 0
3 years ago
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