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allochka39001 [22]
3 years ago
11

If a player rolls 2 dice and gets a sum of 2 or 12, he wins $30. If the person gets a 7, he wins $10. Otherwise he wins nothing.

If the cost to play the game is $3, what does a player expect to get out of this game every time he/she plays?
Mathematics
1 answer:
makkiz [27]3 years ago
7 0

If they were to win $30 they would expect to get $27 in profit.

If they were to win $10 they would expect $7.

If they were to win $0 they would expect $-3 in profit, so technically if they win nothing they lose money.

Hope I could help! :D

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Answer:

0.45134

Step-by-step explanation:

Given that :

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Probability that sample. Proportion falls between 0.59 and 0.62

Using Normal approximation :

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Standard deviation (s) = sqrt(pq/n)

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ax² + bx + c = 0

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First, rewrite the first equation so that the first coefficient is 1. Divide everything by a.

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Isolate (c/a) by subtracting (c/a) from both sides

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x² + (b/a)x = 0 - (c/a)

Add spaces

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Take 1/2 of the middle term's coefficient and square it. Remember that what you add to one side, you add to the other.

x² + (b/a)x + (b/2a)² = -c/a + (b/2a)²

Simplify the left side of the equation.

x² + (b/a)x + (b/2a)² = (x + (b/2a))²

(x + b/2a))² = ((b²/4a²) - (4ac/4a²)) -> ((b² - 4ac)/(4a²))

Take the square root of both sides of the equation

√(x + b/2a))² = √((b²/4a²) - (4ac/4a²))

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Simplify. Isolate the x.

x = -(b/2a) ± (∛b² - 4ac)/2a = (-b ± √(b² - 4ac))/2a

~

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