Any help would be nice

Mathematics

2 answers:

Mashutka [201]3 years ago

7 0

Answer:

$18.75

Step-by-step explanation:

GarryVolchara [31]3 years ago

5 0

Answer:

18.75 I believe is the answer

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Which of the following is true? (1 point)

Soloha48 [4]

2 is true since the absolute value of -6 is 6 and the absolute value of -8 is 8. The absolute value of a number will always be the number itself but positive. Also 6 is less than five which make this true.

4 0

3 years ago

BRAINLIEST!!PLEASE HELP ME

Sauron [17]

divide both sides by a

subtract b from both sides

multiply all terms on both sides by -1
c=b-d/a

5 0

3 years ago

Suppose that an airline overbooks seats on their flights. In particular, it sells 300 tickets for a flight when there are only 2

vladimir1956 [14]

Using the <u>normal approximation to the binomial</u>, it is found that there is a 0.994 = 99.4% probability that we will have enough seats for everyone who shows up.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
The binomial distribution is the probability of <u>x successes on n trials</u>, with <u>p probability</u> of a success on each trial. It can be approximated to the normal distribution with $\mu = np, \sigma = \sqrt{np(1-p)}$ .

In this problem:

15% do not show up, so 100 - 15 = 85% show up, which means that $p = 0.85$ .
300 tickets are sold, hence $n = 300$ .

The mean and the standard deviation are given by:

$\mu = np = 300(0.85) = 255$

$\sigma = \sqrt{np(1-p)} = \sqrt{300(0.85)(0.15)} = 6.185$

The probability that we will have enough seats for everyone who shows up is the probability of at most <u>270 people showing up</u>, which, using continuity correction, is $P(X \leq 270 + 0.5) = P(X \leq 270.5)$ , which is the <u>p-value of Z when X = 270.5</u>.