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2 years ago

What is the domain of the function y =squarerpot of x

Mathematics

1 answer:

adell [148]2 years ago

3 0

Answer: [0,+infiniti)

Step-by-step explanation:

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Easy question:

Delvig [45]

Answer:

3 hours and 45 minutes

Step-by-step explanation:

let's assume the tank has a volume of x liters.

let's assume the speed of filling it is x/6 liters per hour for A and x/10 liters per hour for B.

the formula to calculate the time is:

time = volume / speed

If the pumps work together, the total speed is x/6 + x/10, which is 16/60 x

So the time this takes is:

time = x / (16/60 x) = 60/16 hours = 3.75 hours = 3 hours and 45 minutes.

8 0

2 years ago

The intersection of the two lines, shown in the image below, creates special angle relationships between angles 1,2,3,

levacccp [35]

Answer:

3 and 4

1 and 3

Step-by-step explanation:

This is because these are vertical angles so anything on one side is the same on the other in these words Congruent. Good luck.

5 0

3 years ago

Solve for the variable k.<br><br><br><br> m/k=x

Katyanochek1 [597]

M / k = x.....multiply both sides by k. eliminating the k on the left side
m = xk <==

3 0

3 years ago

Please help me with this question

san4es73 [151]

Step-by-step explanation:

Given: $f'(x) = x^2e^{2x^3}$ and $f(0) = 0$

We can solve for f(x) by writing

$\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx$

Let $u = 2x^3$

$\:\:\:\:du=6x^2dx$

Then

$\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du$

$\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k$

We know that f(0) = 0 so we can find the value for k:

$f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}$

Therefore,

$\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)$

5 0

3 years ago

Whoever solves this correctly will get the brainiest

Igoryamba

Answer:

Step-by-step explanation:

4 0

3 years ago

What is the domain of the function y =squarerpot of x​

What is the domain of the function y =squarerpot of x