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Igoryamba
3 years ago
12

Hello all, I have a short time frame to finish and urgently need help on these 2 problems.

Mathematics
1 answer:
HACTEHA [7]3 years ago
3 0

Answer:

Step-by-step explanation:

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Nine squared divided by three to the fourth power
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Nuetrik [128]
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8 0
3 years ago
Write the equation of a line Parallel to the given line and passes through points (-4, -3); (2, 3). Hints find the slope by usin
julia-pushkina [17]

First, we obtain the gradient (slope) of the first parallel line

\text{gradient, m}_1\text{ = }\frac{y_2-y_1}{x_2-x_1}\text{ = }\frac{3-(-3)}{2-(-4)}=\frac{6}{6}\text{ = 1}

Recall that since both lines are parallel, we have that,

m_1=m_2

Thus

m_2\text{ = 1}

Hence, we can find the equation of the parallel line given that it passes through the points (-4, -3)

Using

\begin{gathered} y\text{ = mx + c} \\ \text{where m = m}_2\text{ = 1} \\ \text{and x = -4 ,  y = -3, we have} \\ -3\text{ = 1(-4) + c} \\ -3\text{ = -4 + c} \\ 4\text{ - 3 = c} \\ c\text{ = 1} \\ \text{Thus, the equation of the line is y = (1)x + 1} \\ y\text{ = x + 1} \end{gathered}

5 0
1 year ago
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goldenfox [79]

Answer:eirther C or D not sure

Step-by-step explanation:

5 0
3 years ago
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