1st one : is 1/4 ( subtract 3/8 from both sides and simplify 5/8 - 3/8 to 1/4. )
2nd one : is 1/2 ( subtract 3/4 from both sides, simplify 1/4 - 3/4 to 1/-2, and then multiply both sides by -1 )
3rd one : is 5/6 ( subtract 1/8 from both sides and simplify 23/24 - 1/8 to 5/6).
0 and 1 are neither prime nor composite. A prime is any number greater than 1 that has just 1 and itself as factors. Primes can only start at x > 1
When that happens (when you start with numbers greater than one) p^2 is a composite consisting of 2 primes, so any composite will obey the law that he number will have at least 3 factors making it up -- in this case p p^2 and 1.
So the answer to the question by definition is that 0 numbers can have the property of both p and p^2 to be prime.
This infinite sum is given by
a
S = ------ but ONLY if r<1. Here, r>1, so the infinite sum does not exist.
1-r
