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zheka24 [161]
3 years ago
6

Keep getting the wrong answer. Please help!!!

Mathematics
1 answer:
givi [52]3 years ago
5 0
C.

9987 × 1.04 = 10386.48
10386.48 - 1950 = 8436.48
8436.48 × .25 = 6327.36
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Suppose you are finding 296 divided by 4 using partial quotients. Is 50 or 70 a more reasonable partial quotient? Explain.
Lyrx [107]
Round 296 up to 300 and then divide 300 by 4 mentally.  Answer:  75.  Which is a more reasonable partial quotient, 50 or 70?
8 0
3 years ago
?<br> 0.07<br> What is 70 x 10^2
Fofino [41]

Answer:

7000

Step-by-step explanation:

I think this is the answer

4 0
3 years ago
Heights of male students in the eighth grade are normally distributed with a mean of 57.2 in. and standard deviation of 2.4 in.
romanna [79]
<span>In statistics finding percentiles relates to the standard deviation and something called a z-score. For normally distributed data the z-score represents how many standard deviations above or below the mean that group is a part of. The z-score for normally distributed data for the 90th percentile is 1.28. The standard deviation is then multiplied by the z-score to find, in this case, the shotlrtest height needed to be in the 90th percentile of this population. In this case to be in the 90th percentile your height must be 60.27 inches.</span>
3 0
3 years ago
4x6.2= 4(6+0.2) = (4x ) + (4 x )
PSYCHO15rus [73]

Answer:

X=3.1

(4•3.1)+(4•3.1)

Step-by-step explanation:

4 of 6.2 is equal to 24.8

4•(6+0.2) = 24.8

4•3.1=12.4•2=24.8

12.4+12.4=24.8

(4x)+(4×)=24.8

5 0
3 years ago
What is the nth term?
kumpel [21]

Let a_k denote the <em>k</em>th term of the sequence. Then

a_k=a_1+d(k-1)

where <em>d</em> is the common difference between consecutive terms in the sequence and <em>a</em>₁ is the first term.

The sum of the first <em>n</em> terms is

S_n=\displaystyle\sum_{k=1}^na_k=a_1+a_2+\cdots+a_{n-1}+a_n

From the formula for a_k, we get

S_n=\displaystyle\sum_{k=1}^n(a_1+d(k-1))=a_1\sum_{k=1}^n1+d\sum_{k=1}^n(k-1)

S_n=\displaystyle na_1+d\sum_{k=0}^{n-1}k

S_n=na_1+\dfrac{d(n-1)n}2

S_n=\dfrac n2(2a_1-d+dn)

So we have d=-5, and 2a_1-d=16 so that a_1=\frac{11}2.

Then the <em>n</em>th term in the sequence is

a_n=\dfrac{11}2-5(n-1)=\boxed{\dfrac{21-10n}2}

7 0
3 years ago
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