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zheka24 [161]
3 years ago
6

Keep getting the wrong answer. Please help!!!

Mathematics
1 answer:
givi [52]3 years ago
5 0
C.

9987 × 1.04 = 10386.48
10386.48 - 1950 = 8436.48
8436.48 × .25 = 6327.36
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Solve (x + 3)2 – 5 = 0 using the quadratic formula.
Harlamova29_29 [7]

Answer:

Step-by-step explanation:

(x+3)² -5 =0 , use the formula (a+b) ² = a²+b²+2ab

x²+9 +6x -5 =0 , combine like terms

x²+6x +4 =0, use the quadratic formula x = (-b±√b²-4ac)/2a

x= (-6 ±√6²-4*1*4)/2*1

x= (-6 ± √36-16) /2

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x=(-6 +2√5)/2 and x=( -6-2√5) /2, factor 2 in the numerator and simplify

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3 years ago
Find the value of x in the triangle
Fofino [41]

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x=63

Step-by-step explanation:

55+62+x=180

117+x=180

180-117=63

x=63

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2 years ago
What is the piecewise-defined function that expresses the cost of the order, C(x), in terms of the number of photos ordered, x?
Murljashka [212]

Answer:

See below

Step-by-step explanation:

The values in the table change by $3.80 from one line to the next. Since each change from line to line changes in number of photos by 20, the average cost per photo is $3.80/20 = $0.19. There is apparently a $5.80 -3.80 = $2.00 shipping charge for numbers of photos in the range shown in the table.

Thus, the piecewise function has 3 pieces:

for x < 100: $2.00 + 0.19x

for x < 200: $4.50 + 0.17x

for x ≥ 200: $0.15x

This could be written as ...

C(x)=\left\{\begin{array}{rcl}\$2.00+0.19x&\text{for}&0\le x

8 0
3 years ago
What is 4 divided by 1/6 anwser asap please
pantera1 [17]

Answer:

0.64

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Let X be the random variable representing the number of calls received in an hour by a 911 emergency service. A portion of the p
ivolga24 [154]

For any distribution, the sum of the probabilities of all possible outcomes must be 1. In this case, we have to have

P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)=1

We're told that p=P(X=1)=P(X=2), and we're given other probabilities, so we have

0.25+2p+0.10+0.05=1\implies2p=0.6\implies p=0.3

The expected number of calls would be

E[X]=\displaystyle\sum_xx\,P(X=x)

E[X]=0\,P(X=0)+1\,P(X=1)+\cdots+4\,P(X=4)

E[X]=1.4

6 0
2 years ago
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