Step-by-step explanation:
Given:
Two Equations
y = x + 5 ..................(1)
y = (3/2) x - 5 ...................(2)
Both are considered as Equation (1) and (2) respectively,
Equating the equation 1 and 2, we get
⇒ x + 5 = (3/2) x - 5
⇒ x - (3/2) x = - 5 - 5
⇒ (2x - 3x) /2 = - 10
⇒ - x = - 20
⇒ x = 20
Now substituting "x = 20" in equation (1), we get
⇒ y = 20 + 5
⇒ y = 25
Thus, we get the value of x = 20 and value of y = 25.
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Step-by-step explanation:
25a⁴ - 10a²z² - 8z⁴ <em>multiply 25*-8 = -200 to find factors (10*-20 = 200), (10 - 20 = -10)</em>
25a⁴ + 10a²z² - 20a²z² - 8z⁴ <em>factor the left two and right two terms</em>
5a²(5a² + 2z²) -4z²(5a² + 2z²) <em>one factor from each side should be identical</em>
= (5a² - 4z²)(5a² + 2z²)
Part A
To find the ticket price when the price is $16
Let us substitute the value of t = 16
p = -10 x (16 x16) + 500 x 16 + 60
p = -2560 + 8000 + 60
p =$ 5500
Part B
To get the maximum profit, we will have to differentiate P with respect to t
The maximum profit will be obtained when the derivative is zero
-20t + 500 = 0
20t = 500
t = 500/20
t = 25
This means that the ticket price has to be $25 so as to obtain the maximum price
Part C
The maximum profit will be obtained by substituting t = 25 into the original equation
Answer:
Step-by-step explanation:
(4x²+15x²)-(-2x²)=19x²+2x²=21x²
