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zimovet [89]
2 years ago
7

Subtract -2x² from the sum of 4x² and 15x².​

Mathematics
2 answers:
tatuchka [14]2 years ago
8 0

Answer:

21x^{2}

Step-by-step explanation:

4x^{2} +15x^{2} --2x^{2}

4x^{2} +15x^{2} +2x^{2}...........2 negatives signs next to each make a positive

21x^{2}.................................combine like terms

harkovskaia [24]2 years ago
6 0

Answer:

Step-by-step explanation:

(4x²+15x²)-(-2x²)=19x²+2x²=21x²

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Given: △ABC, AB=5sqrt2 <br> m∠A=45°, m∠C=30°<br> Find: BC and AC
Marysya12 [62]

BC is 10 units and AC is 5+5\sqrt{3} units

Step-by-step explanation:

Let us revise the sine rule

In ΔABC:

  • \frac{AB}{sin(C)}=\frac{BC}{sin(A)}=\frac{AC}{sin(B)}
  • AB is opposite to ∠C
  • BC is opposite to ∠A
  • AC is opposite to ∠B

Let us use this rule to solve the problem

In ΔABC:

∵ m∠A = 45°

∵ m∠C = 30°

- The sum of measures of the interior angles of a triangle is 180°

∵ m∠A + m∠B + m∠C = 180

∴ 45 + m∠B + 30 = 180

- Add the like terms

∴ m∠B + 75 = 180

- Subtract 75 from both sides

∴ m∠B = 105°

∵ \frac{AB}{sin(C)}=\frac{BC}{sin(A)}

∵ AB = 5\sqrt{2}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{BC}{sin(45)}

- By using cross multiplication

∴ (BC) × sin(30) = 5\sqrt{2} × sin(45)

∵ sin(30) = 0.5 and sin(45) = \frac{1}{\sqrt{2}}

∴ 0.5 (BC) = 5

- Divide both sides by 0.5

∴ BC = 10 units

∵ \frac{AB}{sin(C)}=\frac{AC}{sin(B)}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{AC}{sin(105)}

- By using cross multiplication

∴ (AC) × sin(30) = 5\sqrt{2} × sin(105)

∵ sin(105) = \frac{\sqrt{6}+\sqrt{2}}{4}

∴ 0.5 (AC) = \frac{5+5\sqrt{3}}{2}

- Divide both sides by 0.5

∴ AC = 5+5\sqrt{3} units

BC is 10 units and AC is 5+5\sqrt{3} units

Learn more:

You can learn more about the sine rule in brainly.com/question/12985572

#LearnwithBrainly

6 0
3 years ago
How can I solve this.. Need asap.. Please and thankyou❤️❤️
Elena L [17]
Divide 1500 by 5 to get one fifth of the savings. Multiply that by 12 to get yearly savings. You end up with 3600.
8 0
3 years ago
I REALLY need help with this! Could someone please help me?
denis23 [38]

Answer:

It's the first option

Step-by-step explanation:

The Midsegment Theorem states that the segment connecting the midpoints of two sides of a triangle (in this case AB and  AC) is parallel to the third side (BC) and half as long.

4 0
3 years ago
State the third congruent part to prove the two triangles congruent by SSS. Write the triangle congruence statement
Alekssandra [29.7K]

Answer:

  • ΔCBA ≅ ΔDEF

Step-by-step explanation:

The question in text and on the picture are different.

Going by picture.

When stating the congruence, it is important to stick to right order of vertices.

The first triangle is ΔCBA

<u>Corresponding angles are:</u>

  • ∠C ≅ ∠D, ∠B ≅ ∠E, ∠A ≅ ∠ F

<u>Therefore the second triangle is:</u>

  • ΔDEF
7 0
2 years ago
Read 2 more answers
A runner runs around a circular track. He completes one lap at a time of t = 269 s at a constant speed of v = 4.6 m/s. What is t
AURORKA [14]

Answer:

\boxed{\text{197 m}}

Step-by-step explanation:

The formula relating distance (d), speed (s), and time (t) is

d = st

1. Calculate the distance

d = 269 s × 4.6 m·s⁻¹ = 1240 m

2.Calculate the track radius

The distance travelled is the circumference of a circle

\begin{array}{rcl}C & = & 2 \pi r\\1240 & = & 2 \pi r\\\\r & = & \dfrac{1240}{2 \pi }\\\\& = & 197\\\end{array}\\\text{The radius of the track is }\boxed{\textbf{197 m}}

5 0
3 years ago
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