Answer:
you cant solve for x but
55x/11x=5x
Step-by-step explanation:
Answer:
- Rational: 5.39
- Irrational: √29 ≈ 5.39
Step-by-step explanation:
Any number you can write completely that has a value between the given numbers will be a suitable rational number.
There are many ways to find irrational numbers in the given range. You can make one up, such as ...
... 5.3102003000400005000006...
a non-terminating, non-repeating decimal. (This one has a pattern that makes it easy to extend, but that doesn't make it rational.)
Or, you can use roots, logs, trig functions, exponential functions, or any of the other functions we study that have irrational values. You can add, subtract, or combine them in other ways. (tan(70°)+∛20, for example) For this, I chose √29, because that square root is between the given numbers and 29 is not a perfect square.
Answer:
$22,050
Step-by-step explanation:
$20,000+5%=$21,000
$21,000+5%=$22,050
Answer:
Options 1,2,6,7 are correct statements.
Step-by-step explanation:
In the given figure lines m and n are cut by a transversal t.
Among all the statements the options that are correct are :
1)<1 and <5 are corresponding angles.(The angles in matching corners are called corresponding angles)
2)<3 and <6 are alternate interior angles .(The angles that are formed on opposite sides of the transversal and inside the two lines are alternate interior angles)
6)<4 and <6 are same side consecutive angles.(consecutive angles lie on the same side of the transversal)
7)<1 and <8 are alternate exterior angles.( These angles lie on the exterior side of the lines and on opposite side of the transversal)
Answer:
See Below.
Step-by-step explanation:
Remember multiplicity rules:
- If a factor has an odd multiplicity (e.g. 1, 3, 5...), then the graph will cross the x-axis at that point.
- If a factor has an even multiplicity (e.g. 2, 4, 6...), then the graph will bounce off the x-axis at that point.
From the graph, we can see that at our zeros, the graph always passes through the x-axis.
Hence, we do not have any zeros with even multiplicity since the graph does not "bounce" at any of the zeros.
