7(x + 2) = 6(x + 5)
7x + 14 = 6x + 30 |subtract 14 from both sides
7x = 6x + 16 |subtract 6x from both sides
x = 16
It’d be 2=-2 ... but then subtract two from both side and the answer is a null set. Also known as “no solution”..
Best of luck in your studies :)
-Nicky
We have that
<span>p(t)=-3t^2+18t-4
using a graphing tool, we can see the maximum of the graph
(see the attached figure)
A) </span><span>In what year of operation does Mr. Cash’s business show maximum profit?
</span>
Mr. Cash’s business show maximum profit at year 3 (maximum in the parabole)
<span>B) What is the maximum profit?
23 (hundred of thousand of dollars) = 2.300.000 dollars
</span>c) What time will it be two late?
(This is the time when the graph crosses zero and the profits turn into losses )
5.77 years, or an estimate of about 69 months.
Answer:
The scatter diagram that contains the correlation coefficient closest to r = 1 is the first one shown in the attached images.
Step-by-step explanation:
The correlation coefficient "r" measures how much two variables x and y are related. When the variables are highly related, the value of r is closer to one and the points contained in the scatter diagrams are assimilated more and more to a line. When the value of r is positive the relation is crescent and therefore the slope of the line drawn by the points in the diagram has a positive slope
Therefore, to answer this question, one must search among the attached images for the dispersion diagram in which the points resemble a straight line with a positive slope.
The scatter diagram that meets the requirements mentioned is the first one that appears in the attached images
If one of the numbers we multiply (factors) has zeros at the end, and the other isn't a fraction: all those zeros will stay in the product.
But there might be additional zeros if the other numbers in the factors (the numbers which aren't 0) mupliply to "end" in zero and this is the case here:
8*5=40.
so the product will be 40 and the zeros of the 5000:
40 000
the number of zeros in the product will be bigger than the number of zeros in the factors if the non-zero parts of the fractions multiply to a number with 0 at the end.