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raketka [301]
3 years ago
10

Mr. Klimek made his wife a rectangular vegetable garden. The width is 5 3/4 ft, and the length is 9 4/5 ft. What is the area of

the garden?
Mathematics
1 answer:
pav-90 [236]3 years ago
4 0

Answer: 56 7/20 ft²

Step-by-step explanation: Let's transform the width and the lenght in  improper fractions:

w = 5 3/4 ft, = 4*5+3/4 = 23/4 ft

l = 9 4/5 ft = 5*9+4/5 = 49/5 ft

Area = w * l

A = 23/4 * 49/5 = 1127/20 ft²

1127/20 ⇒ 56 7/20 ft²

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scoundrel [369]

Answer:

answer D

Step-by-step explanation:

hello,

(5x^2-6x+2)(4x^2-3x)=4x^2(5x^2-6x+2)-3x(5x^2-6x+2)\\20x^4-24x^3+8x^2-15x^3+18x^2-6x\\=20x^4-39x^3+26x^2-6x

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6 0
3 years ago
Read 2 more answers
How do i find x in #21
Cerrena [4.2K]
In quadrilaterals inscribed in circles, the sum of opposite angles=180 degrees. so, x+134=180
8 0
3 years ago
Make sure it's fully reduced.<br><br> 2 - x = 5/8
postnew [5]

Isolate the x. Note the equal sign. What you do to one side, you do to the other.

First, subtract 2 from both sides

2 (-2) - x = (5/8) - 2

-x = 5/8 - 2

Make sure they have the same denominator. Remember that what you multiply to the denominator, you multiply the numerator:

-x = 5/8 - 16/8

-x  = - 11/8

Isolate the x. Divide -1 from both sides

(-x)/-1 = (-11/8)/-1

x = 11/8

11/8 is your answer for x

<em>~Rise Above the Ordinary</em>

7 0
4 years ago
2/9 h = 8<br><br> h=<br><br> Pls tell me what h = !
Wewaii [24]

Answer:

h=36

.......................

3 0
3 years ago
Show all work and provide necessary descriptions
masya89 [10]

Let

P=(P_x,P_y),\quad Q=(Q_x,Q_y)

If M is the midpoint, the x and y coordinates of M are the average of the x and y coordinates of P and Q:

M=\left(\dfrac{P_x+Q_x}{2},\ \dfrac{P_y+Q_y}{2}\right)

We can solve this expression for the coordinates of Q:

M_x = \dfrac{P_x+Q_x}{2} \implies Q_x = 2M_x-P_x

M_y = \dfrac{P_y+Q_y}{2} \implies Q_y = 2M_y-P_y

Plug in the values for the coordinates of M and P to get

Q_x = 2M_x-P_x = 2\cdot 5-11 = 10-11=-1

Q_y = 2M_y-P_y = 2\cdot (-2) - (-10) = -4+10=6

5 0
3 years ago
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