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raketka [301]
3 years ago
10

Mr. Klimek made his wife a rectangular vegetable garden. The width is 5 3/4 ft, and the length is 9 4/5 ft. What is the area of

the garden?
Mathematics
1 answer:
pav-90 [236]3 years ago
4 0

Answer: 56 7/20 ft²

Step-by-step explanation: Let's transform the width and the lenght in  improper fractions:

w = 5 3/4 ft, = 4*5+3/4 = 23/4 ft

l = 9 4/5 ft = 5*9+4/5 = 49/5 ft

Area = w * l

A = 23/4 * 49/5 = 1127/20 ft²

1127/20 ⇒ 56 7/20 ft²

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Can anyone help? Thank you.
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Answer:

  91.8 ft

Step-by-step explanation:

So we can talk about the diagram, let's name a couple of points. The base of the tree is point T, and the top of the tree is point H. We want to find the length of TH given the length AB and the angles HAT and ABT.

The tangent function is useful here. By its definition, we know that ...

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Then we can solve for TH by substituting for TA. From the first equation, ...

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From the second equation, ...

  TH = TA·tan(∠HAT) = (BA·tan(∠ABT))·tan(∠HAT)

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  TH = (24.8 ft)tan(87.3°)tan(9.9°) ≈ 91.8 ft

The height <em>h</em> of the tree is about 91.8 ft.

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