I think the first one or the thrid one
hope this help
Answer:
Step-by-step explanation:
this is the same equation, the system has infinitely many solutions
Answer:
ln|sec θ + tan θ| + C
Step-by-step explanation:
The integrals of basic trig functions are:
∫ sin θ dθ = -cos θ + C
∫ cos θ dθ = sin θ + C
∫ csc θ dθ = -ln|csc θ + cot θ| + C
∫ sec θ dθ = ln|sec θ + tan θ| + C
∫ tan θ dθ = -ln|cos θ| + C
∫ cot θ dθ = ln|sin θ| + C
The integral of sec θ can be proven by multiplying and dividing by sec θ + tan θ, then using ∫ du/u = ln|u| + C.
∫ sec θ dθ
∫ sec θ (sec θ + tan θ) / (sec θ + tan θ) dθ
∫ (sec² θ + sec θ tan θ) / (sec θ + tan θ) dθ
ln|sec θ + tan θ| + C
Answer:
2 2/9
Step-by-step explanation:
6 1/3 - 4 1/9
1/3: 1x3 3x3= 3/9
1/9: 1x1 9x1= 1/9
3/9 - 1/9 = 2/9
6-4=2
Answer: 2 2/9
