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hammer [34]
3 years ago
6

Find the value of x 3(4x+3)

Mathematics
1 answer:
Dimas [21]3 years ago
8 0

3(4x+3)=12x+9

i don't know what do you need,

if roots, let 12x+9=0

the root is x=-3/4

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Please show work and solve :)
andreyandreev [35.5K]

Answer:

c = 24

Step-by-step explanation:

1/3c - 7 = 1

add 7 to both sides

1/3c = 8

now multiply 3 to both sides

c = 24

7 0
2 years ago
Read 2 more answers
Question 8 Find the unit vector in the direction of (2,-3). Write your answer in component form. Do not approximate any numbers
slamgirl [31]

Answer:

The unit vector in component form is \hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right) or \hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j.

Step-by-step explanation:

Let be \vec u = (2,-3), its unit vector is determined by following expression:

\hat {u} = \frac{\vec u}{\|\vec u \|}

Where \|\vec u \| is the norm of \vec u, which is found by Pythagorean Theorem:

\|\vec u\|=\sqrt{2^{2}+(-3)^{2}}

\|\vec u\| = \sqrt{13}

Then, the unit vector is:

\hat{u} = \frac{1}{\sqrt{13}} \cdot (2,-3)

\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right)

The unit vector in component form is \hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right) or \hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j.

6 0
3 years ago
............... help me please i don’t understand this
Sergio [31]

Answer:

x = 11

Step-by-step explanation:

3 0
3 years ago
Plz help ASAP! thank u
LiRa [457]

Answer: Choice B)

The relation is a function because there are no vertical lines that can be drawn on the graph that pass through more than one point.

This graph passes the vertical line test. Any input (x) leads to one and only one output (y). An example of a graph failing the vertical line test would be a graph that is a sideways parabola.

4 0
3 years ago
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8. What is the surface area of the given figure?
Liono4ka [1.6K]

Answer:

C. 336 cm²

Step-by-step explanation:

Area formulas:

Area of a right triangle: a × b ÷ 2

Area of rectangle: length × width

-----------------------------------------------------------------------------------------------------------------

In this figure, there is a rectangle with a width of 12 and a height of 6.

; the area of the rectangle is 72 cm².

There are two right triangles with legs of 6 and 8.

There are two right triangles so..

The area of a single triangle is 24 cm²; the area of the triangles combined is 48 cm.

There is a rectangle in the middle with a width of 8 and a height of 12.

The area of the rectangle is 96 cm².

Lastly, there is a rectangle with a width of 10 and a height of 12.

The area of the rectangle is 120 cm².

Now, add the areas of every shape to find your answer.

Step-by-step explanation:

3 0
2 years ago
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