The paper usage at a small copy center is normally distributed with a mean of 5 boxes of paper per week, and a standard deviatio
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Answer:
Test statistic = -2.25
P-value = 0.0199
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 450 gram
Sample mean, = 441 grams
Sample size, n = 16
Alpha, α = 0.05
Sample variance = 256
First, we design the null and the alternate hypothesis
We use one-tailed t test to perform this hypothesis.
Formula:
Putting all the values, we have
Now,
Degree of freedom =
We can calculate the p-value from the table as:
P-value = 0.0199
Conclusion:
Since the p-value is smaller than the significance level we fail to accept the null hypothesis and reject it.
Thus, there is enough evidence to support the claim that the machine is under filling the bags .