Answer:
It's B, I'm only trying my best since there is no picture.
Step-by-step explanation:
Answer:
min = a_1
for i:= 2 to n:
if
< min then min = 
return min
Step-by-step explanation:
We call the algorithm "minimum" and a list of natural numbers 
So lets first set the minimum to 
min = a_1
now we want to check all the other numbers.
We can use a simple for loop, to find the minimum
min = a_1
for i:= 2 to n:
if
< min then min = 
return min
Answer:
yes
Step-by-step explanation:i am also right lol