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3 years ago

A student bought a piece of hard candy that is in the shape of a sphere. The candy has a radius of 3 centimeters.

Mathematics

1 answer:

worty [1.4K]3 years ago

3 0

Volume of piece candy is 113.04 cubic centimeter

Solution:

A student bought a piece of hard candy that is in the shape of a sphere

The candy has a radius of 3 centimeters

Radius = 3 cm

Use 3.14 for π

Volume of sphere is given as:

$V = \frac{4}{3} \times \pi \times r^3$

Where, "r" is the radius of sphere

Therefore, volume of candy is given as:

$V = \frac{4}{3} \times 3.14 \times 3^3\\\\V = 4 \times 3.14 \times 3^2\\\\V = 12.56 \times 9\\\\V = 113.04$

Thus volume of candy is 113.04 cubic centimeter

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Using the formula F=9/5C+32, find C when F= 75.

den301095 [7]

Answer:

DIVIDING 9 AND 5 = 23.8

9/5 FRACTION = 0.04

Step-by-step explanation:

If 9/5 means 9 divided by 5

FLIP THE EQUATION

9/5C + 32 = 75

9/5C + 32 - 32 = 75 -32

9/5C = 43

9/5 = 1.8

1.8C = 43

1.8C/1.8 = 4

If 9/5 means 9/5ths fraction

FLIP THE EQUATION

9/5C + 32 = 75

9/5C + 32 - 32 = 75 -32

9/5C = 43

9/5C / 9/5 = 43 / 9/5

C = 0.04

Hope this helps i thought 9/5 was 9 divide by 5. If it was 9/5 as a fraction i also made that equation too.

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3 years ago

Consider an experiment where two 6-sided dice are rolled. We can describe the ordered sample space as below where the first coor

agasfer [191]

Answer:

$E$ = { (4,1) , (3,2) , (2,3) , (1,4) }

$P(E)=\frac{1}{9}$

$P(F|E)=\frac{1}{4}$

Step-by-step explanation:

Let's start writing the sample space for this experiment :

$S=$ { (1,1) , (1,2) , (1,3) , (1,4) , (1,5) , (1,6) , (2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6) , (3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (3,6) , (4,1) , (4,2) , (4,3) , (4,4) , (4,5) , (4,6) , (5,1) , (5,2) , (5,3) , (5,4) , (5,5) , (5,6) , (6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6) }

Let's also define the event $E$ ⇒

$E$ : '' The sum of the two dice is 5 ''

We can describe the event by listing all the favorables cases from $S$ ⇒

$E$ = { (4,1) , (3,2) , (2,3) , (1,4) }

In order to calculate $P(E)$ we are going to divide all the cases favorables to $E$ over the total cases from $S$ . We can do this because all 36 of these possible outcomes from $S$ are equally likely. ⇒

$P(E)=\frac{4}{36}=\frac{1}{9}$ ⇒

$P(E)=\frac{1}{9}$

Finally we are going to define the event $F$ ⇒

$F$ : '' The number of the first die is exactly 1 more than the number on the second die ''

⇒

$F$ = { (2,1) , (3,2) , (4,3) , (5,4) , (6,5) }

Now given two events A and B ⇒

P ( A ∩ B ) = $P(A,B)$

We define the conditional probability as

$P(A|B)=\frac{P(A,B)}{P(B)}$ with $P(B)>0$

We need to find $P(F|E)$ therefore we can apply the conditional probability equation :

$P(F|E)=\frac{P(F,E)}{P(E)}$ (I)

We calculate $P(E)=\frac{1}{9}$ at the beginning of the question. We only need $P(F,E)$ .

Looking at the sets $E$ and $F$ we find that (3,2) is the unique result which is in both sets. Therefore is 1 result over the 36 possible results. ⇒

$P(F,E)=\frac{1}{36}$

Replacing both probabilities calculated in (I) :

$P(F|E)=\frac{P(F,E)}{P(E)}=\frac{\frac{1}{36}}{\frac{1}{9}}=\frac{1}{4}=0.25$

We find out that $P(F|E)=\frac{1}{4}=0.25$

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Step-by-step explanation:

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Which expression can be used to find measure angle R

Novay_Z [31]

Answer:

cos-1(-4/14)

Step-by-step explanation:

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3.5=s

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By law of cosines:

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3 years ago

In the given figure, angle APC = angle BQD. Prove that: AB //CD.

aniked [119]

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3. AB//CD [From 2]

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3 years ago