Answer:
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Answer:
common ratio: 1.155
rate of growth: 15.5 %
Step-by-step explanation:
The model for exponential growth of population P looks like: 
where
is the population at time "t",
is the initial (starting) population
is the common ratio,
and
is the rate of growth
Therefore, in our case we can replace specific values in this expression (including population after 12 years, and initial population), and solve for the unknown common ratio and its related rate of growth:
![P(t)=P_i(1+r)^t\\13000=2300*(1+r)^{12}\\\frac{13000}{2300} = (1+r)^12\\\frac{130}{23} = (1+r)^{12}\\1+r=\sqrt[12]{\frac{130}{23} } =1.155273\\](https://tex.z-dn.net/?f=P%28t%29%3DP_i%281%2Br%29%5Et%5C%5C13000%3D2300%2A%281%2Br%29%5E%7B12%7D%5C%5C%5Cfrac%7B13000%7D%7B2300%7D%20%3D%20%281%2Br%29%5E12%5C%5C%5Cfrac%7B130%7D%7B23%7D%20%3D%20%281%2Br%29%5E%7B12%7D%5C%5C1%2Br%3D%5Csqrt%5B12%5D%7B%5Cfrac%7B130%7D%7B23%7D%20%7D%20%3D1.155273%5C%5C)
This (1+r) is the common ratio, that we are asked to round to the nearest thousandth, so we use: 1.155
We are also asked to find the rate of increase (r), and to express it in percent form. Therefore we use the last equation shown above to solve for "r" and express tin percent form:

So, this number in percent form (and rounded to the nearest tenth as requested) is: 15.5 %
Answer:
d. c = 100; (x – 10)²
Step-by-step explanation:
Note that (x+a)²=x²+2ax+a².
In our case, 2a=-20, so 'a' must be -10.
Since c=a², and a=-10, c=(-10²)=100.
Since a=-10, the perfect square is (x – 10)²
It is 3y because of the calculation being equivalent
9514 1404 393
Answer:
- 8 years: Rs. 64
- 9 years: Rs. 72
- 10 years: Rs. 80
Step-by-step explanation:
The sum of ages is 8+9+10 = 27, so each year of age is rewarded by ...
216/27 = 8 . . . Rs
Then age 8 gets 8(Rs. 8) = Rs. 64
age 9 gets 9(Rs. 8) = Rs. 72
age 10 gets 10(Rs. 8) = Rs. 80