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3 years ago

Subtract the fraction and simplify the answer 13/15 - 1/5

1 answer:

8 0

First, make sure that there is a common denominator, or in other words, the denominators, are the same.

You have the numbers 15 and 5 and the lowest common multiple between the two is 15, and in order to make sure the denominators are both the same, you multiply 5 by 3.

Now, whatever you do to the bottom, you make sure you do to the top. In other words, multiply the numerator by 3 as well, and the second fraction is now 3/15. You can now subtract 3 from 13 and the answer is 10/15. You can reduce that to 2/3 by factoring out a 5.

13/15 - 1/5 --> 13/15 - 3/15 = 10/15 --> 2/3

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I need to find the product help

Licemer1 [7]

I'm assuming you mean

$2\times\frac{17}{10}$

Write the 2 as a fraction 2/1 and multiply.

$\frac{2}{1}\times\frac{17}{10}=\frac{34}{10}=\frac{17}{5}$

7 0

3 years ago

At the arcade, Sami won 2 blue tickets, 1 yellow ticket, and 3 red tickets for 1500 total points. Jamie won 1 blue ticket, 2 yel

aleksandrvk [35]

Answer:

$\left[\begin{array}{ccc}2&1&3\\1&2&2\\2&3&1\end{array}\right]$ $\left[\begin{array}{c}b&y&r\end{array}\right]$ $= \left[\begin{array}{c}1500&1225&1200\end{array}\right]$

Step-by-step explanation:

Given

$b = blue$

$y = yellow$

$r = red$

Required

Represent as a matrix

For Sammy:

$2\ blue + 1\ yellow + 3\ red =1500$

So, we have:

$2b + 1y + 3r = 1500$

$2b + y + 3r = 1500$

For Jamie:

$1\ blue + 2\ yellow + 2\ red =1225$

So, we have:

$1b + 2y + 2r = 1225$

$b + 2y + 2r = 1225$

For Yvonne:

$2\ blue + 3\ yellow + 1\ red =1200$

So, we have:

$2b + 3y + 1r = 1200$

$2b + 3y + r = 1200$

The system of equations are:

$2b + y + 3r = 1500$

$b + 2y + 2r = 1225$

$2b + 3y + r = 1200$

To represent as a matrix, we have:

$\left[\begin{array}{ccc}b_1&y_1&r_1\\b_2&y_2&r_2\\b_3&y_3&r_3\end{array}\right]$ $\left[\begin{array}{c}b&y&r\end{array}\right]$ $= \left[\begin{array}{c}Total_1&Total_2&Total_3\end{array}\right]$

This gives:

$\left[\begin{array}{ccc}2&1&3\\1&2&2\\2&3&1\end{array}\right]$ $\left[\begin{array}{c}b&y&r\end{array}\right]$ $= \left[\begin{array}{c}1500&1225&1200\end{array}\right]$

3 0

3 years ago

Differentiate y=x⁴(1-2x⁵)⁶(5-8x³)².

Liula [17]

Step-by-step explanation:

Let $y(x)=f(x)g(x)h(x)$ where