I think its 1/2…hope this helps id it dont then.....:\¯\_(ツ)_/¯
Answer:
19
or 18
Step-by-step explanation:
First, add the whole numbers
3, 7, and 8
18
Add the fractions
+
=
IF YOU WANT SIMPLIFIED NUMBER DO THIS
=1
18+1=19
-- They're losing employees . . . so you know that the line will slope down, and
its slope is negative;
-- They're losing employees at a steady rate . . . so you know that the slope is
the same everywhere on the line; this tells you that the graph is a straight line.
I can see the function right now, but I'll show you how to go through the steps to
find the function. I need to point out that these are steps that you've gone through
many times, but now that the subject pops up in a real-world situation, suddenly
you're running around in circles with your hair on fire screaming "What do I do ?
Somebody give me the answer !".
Just take a look at what has already been handed to you:
0 months . . . 65 employees
1 month . . . . 62 employees
2 months . . . 59 employees
You know three points on the line !
(0, 65) , (1, 62) , and (2, 59) .
For the first point, 'x' happens to be zero, so immediately
you have your y-intercept ! ' b ' = 65 .
You can use any two of the points to find the slope of the line.
You will calculate that the slope is negative-3 . . . which you
might have realized as you read the story, looked at the numbers,
and saw that they are <u>firing 3 employees per month</u>.
("Losing" them doesn't quite capture the true spirit of what is happening.)
So your function ... call it ' W(n) ' . . . Workforce after 'n' months . . .
is <em>W(n) = 65 - 3n</em> .
Proving a relation for all natural numbers involves proving it for n = 1 and showing that it holds for n + 1 if it is assumed that it is true for any n.
The relation 2+4+6+...+2n = n^2+n has to be proved.
If n = 1, the right hand side is equal to 2*1 = 2 and the left hand side is equal to 1^1 + 1 = 1 + 1 = 2
Assume that the relation holds for any value of n.
2 + 4 + 6 + ... + 2n + 2(n+1) = n^2 + n + 2(n + 1)
= n^2 + n + 2n + 2
= n^2 + 2n + 1 + n + 1
= (n + 1)^2 + (n + 1)
This shows that the given relation is true for n = 1 and if it is assumed to be true for n it is also true for n + 1.
<span>By mathematical induction the relation is true for any value of n.</span>
