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s2008m [1.1K]
3 years ago
13

I need help asap!

Mathematics
1 answer:
k0ka [10]3 years ago
6 0

Answer:

AC and BC are 3\sqrt{2} or 4.24

Step-by-step explanation:

AC=BC and AB = 6 units

Let AC=BC=x units

AB^2=AC^2+BC^2\\6^2=x^2+x^2\\6^2=2x^236=2x^2\\x^2=18\\x=\sqrt{18} =3\sqrt{2}

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A 50 foot rope weighing a total of 32 lbs extended over a cliff that is 35 feet to the ground. A large 8 pound bucket with 19 ga
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Answer:

A function that gives the work required in foot-lbs to lift the bucket up x feet from the ground is W=16(50-x)+(19-\frac{x}{5})(8.3)x and  the work to get the bucket to the top of the cliff is 3726 foot-lbs

Step-by-step explanation:

Work done to lift the rope by distance x feet:

W_1=32(\frac{50-x}{2})

Work done to lift the bucket by distance x feet:

W_2=(19-\frac{x}{5})(8.3)x

On reaching top 7 gallons of water spilled out so , on going up by x feet \frac{7x}{35}=\frac{x}{5} gallons of water spilled out.

a function that gives the work required in foot-lbs to lift the bucket up x feet from the ground:

W=16(50-x)+(19-\frac{x}{5})(8.3)x

Now the work to get the bucket to the top of the cliff i.e. x =35

W=16(50-35)+(19-\frac{35}{5})(8.3)(35)

W=3726

Hence, a function that gives the work required in foot-lbs to lift the bucket up x feet from the ground is W=16(50-x)+(19-\frac{x}{5})(8.3)x and  the work to get the bucket to the top of the cliff is 3726 foot-lbs

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