Formula of the midpoint:
x =(x₁+x₂)/2 and y = (y₁+y₂)/2
Plugin the respective value
for A(0,1/2) and B(0, 3/4)
x= (0+0)/2 = 0
y = (1/2 + 3/4)/2 = 5/8
Then the midpoint of the line segment whose endpoints are (0,1/2 ) and (0,3/4 ). is M(0, 5/8) or M(0, 0.625)
Answer:
The mean.
Step-by-step explanation:
I would use the mean as the measure of central tendency.
It is the best representation of the data as the variability isn't high; I'd only use the median if outliers are present because outliers don't affect it.
Because there are no outliers here, the mean is better.
Hopefully I helped :)
