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Sholpan [36]
3 years ago
6

The equation 13x + 1 = 5 – x can be solved by graphing y = 13x + 1 and y = 5 – x.

Mathematics
1 answer:
shusha [124]3 years ago
7 0

Answer:

The graph shows that when x =3 both

\frac{1}{3}x + 1

and 5 – x equal 2

Step-by-step explanation:

The equation 13x + 1 = 5 – x can be solved by graphing y = 13x + 1 and y = 5 – x.

From the graph, the two lines representing the two equations intersect at (3,2).

This implies that the solution to the system

y =  \frac{1}{3} x + 1

and

y=5-x

is x=3, y=2

Hence the value of the two functions equals 2 at x=3.

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Answer:

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Step-by-step explanation:

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3 years ago
use the intermediate value theorem to determine whether the following equation has a solution or not x^3-3x-1
xxTIMURxx [149]

Answer:

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Step-by-step explanation:

Hi there!

1) Remember a definition.

Intermediate Value Theorem:

If f is continuous on a given closed interval [a,b], and f(a)≠f(b) and f(a)<k<f(b) then there has to be at least one number 'c' between 'a' and 'b', such that f(c)=k

----

(Check the first graph as an example)

2) The Intermediate Value Theorem can be applied to determine whether there is a solution on a given interval.

Let's choose the interval [0,2]

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Proceed to the other point: 2

f(x)=x^{3}-3x-1\\f(2)=(2)^{3}-3(2)-1\\f(2)=1\\f(2)>0\\

3) Check the 2nd Graph for a the Visual answer, of it.  And the 3rd graph for all solutions of this equation.

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Read 2 more answers
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