Simplify the followin expression.x^4+3x^3-2x^3-5x^2-x+x^2+x+1+7x^4
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Answer:
x = 12
Step-by-step explanation:
Given a tangent and a secant from an external point to the circle, then
The square of the tangent is equal to the product of the external part and the entire secant, that is
x² = 6(6 + 18) = 6 × 24 = 144 ( take the square root of both sides )
x = = 12