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seraphim [82]
3 years ago
6

The figure below is a net for a rectangular prism. Side a = 69 centimeters, side b = 22 centimeters, and side c = 15 centimeters

. What is the surface area of this figure?
Note: Figure is not drawn to scale.
A.
2,883 square centimeters
B.
3,765 square centimeters
C.
2,745 square centimeters
D.
5,766 square centimeters
Mathematics
1 answer:
Whitepunk [10]3 years ago
7 0

Answer: The answer should b C good luck!

Step-by-step explanation:

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What is the value of k if 7k" minutes past nine" is the same as 8k" minutes to ten"?
schepotkina [342]

Answer:

4 minutes

Step-by-step explanation:

The value of 7k "minutes past nine" is the same as 8k" minutes to ten".

Since there are 60 minutes in an hour and 9 and 10 fall in between the same hour, this means that:

7k = 60 - 8k

7k + 8k = 60

15k = 60

k = 60 / 15

k = 4 minutes

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Which set of numbers could be the length of the sides of a triangle?
san4es73 [151]

3. {6,9,15)

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I need help. It's kinda hard for me. We have to use decimal numbers
cestrela7 [59]

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Step-by-step explanation:

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3 years ago
What is the quotient when (x+3) is divided into the polnomial 2x^2+x-15
Alika [10]

Answer:

2x-5

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Step-by-step explanation:

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7 0
3 years ago
If you want to be 95​% confident of estimating the population mean to within a sampling error of plus or minus3 and the standard
Aleksandr [31]

Answer:

The sample size required is at least 171

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

What sample size is​ required?

A samle size of at least n is required, in which n is found when M = 3, \sigma = 20

So

M = z*\frac{\sigma}{\sqrt{n}}

3 = 1.96*\frac{20}{\sqrt{n}}

3\sqrt{n} = 20*1.96

\sqrt{n} = \frac{20*1.96}{3}

(\sqrt{n})^{2} = (\frac{20*1.96}{3})^{2}

n = 170.7

Rouding up

The sample size required is at least 171

5 0
3 years ago
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