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melisa1 [442]
3 years ago
8

Solve. 7(2y-10)=14. What is the awnser

Mathematics
2 answers:
tamaranim1 [39]3 years ago
6 0

Awnser: y=38.50

Step-by-step explanation:

7 times 2y and 7 times 10

7 times 2y - 70

add 70 to 14

7 times 2y = 84

84 minus 7 =77

77 divided by 2 =38.50

Sergeu [11.5K]3 years ago
3 0

Answer:

y = 6

Step-by-step explanation:

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Alchen [17]

Answer:

the answer is -24

Step-by-step explanation:

7 0
3 years ago
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Y=8x;(0,0) help please it is due tmr
nlexa [21]
(X,Y) 0=X and 0=Y if you plug in 0 for X and 0 for Y in Y=8X it will be 0=8(0). 8 times 0 is 0 which is the equation
6 0
4 years ago
1)Sheyna drive to the lake and back. It took two hours less time to get there than it did to get back. The average speed on the
ipn [44]

Answer:

8 hours

Step-by-step explanation:

Given:

Sheyna drives to the lake with average speed of 60 mph and

v_1 = 60\ mph

Sheyna drives back from the lake with average speed of 36 mph

v_2 = 36\ mph

It took 2 hours less time to get there than it did to get back.

Let t_1 be the time taken to drive to lake.

Let t_2 be the time taken to drive back from lake.

t_2-t_1 = 2 hrs ..... (1)

To find:

Total time taken = ?

t_1+t_2 = ?

Solution:

Let D be the distance to lake.

Formula for time is given as:

Time =\dfrac{Distance}{Speed }

t_1 = \dfrac{D}{60}\ hrs

t_2 = \dfrac{D}{36}\ hrs

Putting in equation (1):

\dfrac{D}{36}-\dfrac{D}{60} = 2\\\Rightarrow \dfrac{5D-3D}{180} = 2\\\Rightarrow \dfrac{2D}{180} = 2\\\Rightarrow D = 180\ miles

So,

t_1 = \dfrac{180}{60}\ hrs = 3 \ hrs

t_2 = \dfrac{180}{36}\ hrs = 5\ hrs

So, the answer is:

t_1+t_2 = \bold{8\ hrs}

8 0
3 years ago
What is the equation of the line that is perpendicular to the given line and passes through the point (5,3)
Pani-rosa [81]

perpendicular lines have a slope that is a negative reciprocal


A) 4x-5y=5

subtract 4x

solve for y

-5y = -4x+5

divide by -5

y = 4/5 x+5   slope is 4/5  perpendicular slope is -5/4

y -y1 =m(x-x1)  point slope form of a line

y-3 = -5/4 (x-5)

B)  5x+4y = 37

subtract 5x

4y =-5x +37

divide by 4

y =-5/4 x +37/4  slope is -5/4 perpendicular slope is 4/5

y -y1 =m(x-x1)  point slope form of a line

y-3 = 4/5 (x-5)

C)4x+5y=5

subtract 4x

5y = -4x +5

divide by 5

y = -4/5 x +1

y =-4/5 x +1  slope is -4/5 perpendicular slope is 5/4

y -y1 =m(x-x1)  point slope form of a line

y-3 = 5/4 (x-5)

D)5x-4y=8

subtract 5x

-4y = -5x+8

divide by -4

y = 5/4 x-2

y =5/4 x +-2 slope is 5/4 perpendicular slope is -4/5

y -y1 =m(x-x1)  point slope form of a line

y-3 = -4/5 (x-5)



6 0
4 years ago
Can some one help me please
frutty [35]
I believe The answer is B
6 0
3 years ago
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