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Marizza181 [45]
2 years ago
8

The radius of a circle is 4 centimeters.what is the area

Mathematics
1 answer:
tester [92]2 years ago
7 0
A= 50.27 cm^2 :) hopefully this is right
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Find the distance between the points (-9,2) and (-1,4). Round to the nearest tenth if necessary.
AlekseyPX

Answer:

The answer to the nearest tenth is 8.2

Step-by-step explanation:

In order to find the distance between any two points, you must use the distance formula. when you plug in the points into the formula you end up with 8.246, rounded to the nearest tenth would be 8.2. I hope this helps!

8 0
3 years ago
What are ALL the factors of 15
Sophie [7]
1&15 and 3&5 are factors of 15
3 0
3 years ago
On field day, Breanna long jumped 62 inches, Myquisha jumped 5 feet 4 inches, and Ariana jumped 1 yard, 2 feet, 7 inches. Which
ella [17]
Let’s convert all their jumps into inches.

Breanna’s is already in inches (62)

Myquisha jumped 5 feet 4 inches
There are 12 inches in a foot, so

5 feet * 12 inches= 60 inches

Then add the 4 inches
60+4= 64
So Myquisha jumped 64 inches.


Ariana jumped 1 yard, 2 feet, 7 inches

1 yard is equal to 3 feet.

So, she jumped 5 feet 7 inches

12 inches in a foot, so
5*12=60 inches

Add the 7
60+7= 67 inches

So Breanna jumped 62, Myquisha 64 and Ariana 67

In order of shortest to longest:

Breanna, Myquisha, Ariana
3 0
3 years ago
Read 2 more answers
Find the two intersection points
bogdanovich [222]

Answer:

Our two intersection points are:

\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)

Step-by-step explanation:

We want to find where the two graphs given by the equations:

\displaystyle (x+1)^2+(y+2)^2 = 16\text{ and } 3x+4y=1

Intersect.

When they intersect, their <em>x-</em> and <em>y-</em>values are equivalent. So, we can solve one equation for <em>y</em> and substitute it into the other and solve for <em>x</em>.

Since the linear equation is easier to solve, solve it for <em>y: </em>

<em />\displaystyle y = -\frac{3}{4} x + \frac{1}{4}<em />

<em />

Substitute this into the first equation:

\displaystyle (x+1)^2 + \left(\left(-\frac{3}{4}x + \frac{1}{4}\right) +2\right)^2 = 16

Simplify:

\displaystyle (x+1)^2 + \left(-\frac{3}{4} x  + \frac{9}{4}\right)^2 = 16

Square. We can use the perfect square trinomial pattern:

\displaystyle \underbrace{(x^2 + 2x+1)}_{(a+b)^2=a^2+2ab+b^2} + \underbrace{\left(\frac{9}{16}x^2-\frac{27}{8}x+\frac{81}{16}\right)}_{(a+b)^2=a^2+2ab+b^2} = 16

Multiply both sides by 16:

(16x^2+32x+16)+(9x^2-54x+81) = 256

Combine like terms:

25x^2+-22x+97=256

Isolate the equation:

\displaystyle 25x^2 - 22x -159=0

We can use the quadratic formula:

\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = 25, <em>b</em> = -22, and <em>c</em> = -159. Substitute:

\displaystyle x = \frac{-(-22)\pm\sqrt{(-22)^2-4(25)(-159)}}{2(25)}

Evaluate:

\displaystyle \begin{aligned} x &= \frac{22\pm\sqrt{16384}}{50} \\ \\ &= \frac{22\pm 128}{50}\\ \\ &=\frac{11\pm 64}{25}\end{aligned}

Hence, our two solutions are:

\displaystyle x_1 = \frac{11+64}{25} = 3\text{ and } x_2 = \frac{11-64}{25} =-\frac{53}{25}

We have our two <em>x-</em>coordinates.

To find the <em>y-</em>coordinates, we can simply substitute it into the linear equation and evaluate. Thus:

\displaystyle y_1 = -\frac{3}{4}(3)+\frac{1}{4} = -2

And:

\displaystyle y _2 = -\frac{3}{4}\left(-\frac{53}{25}\right) +\frac{1}{4} = \frac{46}{25}

Thus, our two intersection points are:

\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)

6 0
3 years ago
Part A:
shusha [124]

Part A:

Six Tents Holds 42 People

Nine Tents Holds 63 People

10 Tents Holds 70 People

Part B:

Number of tents|||Number of people

1                          |||7

6                         |||42

9                         |||63

10                        |||70

Part C:

Tents=x

1x=7 people

8 0
3 years ago
Read 2 more answers
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