That is the final answer to this question
42765
Find the mean, median, mode, and range of this data: 49, 49, 54, 55, 52, 49, 55. If necessary, round to the nearest tenth.
Zigmanuir [339]
The mean is the average.
So, to find the mean you want o add up all of the numbers and then divide by the number of numbers.
49 + 49 + 54 + 55 + 52 + 49 + 575 = 363
363 / 7 = 51.85
Rounded to 52
For the median you want o line all of your number up from least to greatest and then find the middle number.
49,49,49,52,54,55,55
Your median is 52
The mode is the number that is listed most often
49 is listed 3 times
54 is listed 1 time
52 is listed 1 time
55 is listed 2 times
So, your mode is 49
<span>3.3l : 900ml
= 3300 ml / 900 ml = 33/9 </span>
Answer:
b = 33m is the answer
Step-by-step explanation:
a = 44m
b = ?
c = 55m
According to the Pythagoras theorem,
a² + b² = c²
44² + b² = 55²
1936 + b² = 3025
b² = 3025 - 1936
b² = 1089
b = 33m
∴ b = 33m is the length of the missing leg.
