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rewona [7]
3 years ago
5

Please help.........................................................

Mathematics
2 answers:
Dmitry [639]3 years ago
5 0
Order of operations
pemdas
first do parnthaeses, inside to out
then exponents
then mulitply or divide
then add or subtract


so

40/(24-4(2+3))
inside to out
2+3=5

now we has
40/(24-4(5))
multiply inside parntahes
-4(5)=-20

now we has
40/(24-20)
subtract inside parenthasees

now we has
40/4
divide
10
Inessa05 [86]3 years ago
4 0
It all comes down to 40/0 which would technically be infinity, but in this case, the answer would be 40.

hope this helps
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Answer:

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Step-by-step explanation:

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Jessica saved a total of $58.50 to spend on school supplies. She wants to buy one backpack for $36.25 and she wants to spend the
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The height, h, of a falling object t seconds after it is dropped from a platform 300 feet above the ground is modeled by the fun
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If a ball is thrown into the air with a velocity of 34 ft/s, its height (in feet) after t seconds is given by y = 34t − 16t2. Fi
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<u>ANSWER: </u>

If a ball is thrown into the air with a velocity of 34 feet per second, then velocity of the ball after 1 second is 2 feet per second

<u>SOLUTION: </u>

Given, a ball is thrown into the air with a velocity of 34 feet per second

Initial velocity (u) = 34 feet per second

And also given a relation between displacement and time = \mathrm{y}=34 \mathrm{t}-16 \mathrm{t}^{2} --- eqn 1

We need to find the velocity when t = 1 ; v = ?

We know that, v = u + at and \mathrm{s}=\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}

where v is instantaneous velocity and u is initial velocity

a is acceleration

t is time interval  

s is displacement

using the displacement and time relation eqn (1) we get

Now, when t = 1, displacement s = 34(1) – 16(1)

\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}=34-16

34 \times 1+\frac{1}{2} \times a \times 1^{2}=18

34+\frac{a}{2}=18

\begin{array}{l}{\frac{a}{2}=18-34} \\\\ {\frac{a}{2}=-16} \\ {a=-16 \times 2} \\ {a=-32}\end{array}

here, -ve sign indicates that object is in deceleration . so acceleration is -32 ft/s

now put a value in v = u + at

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v = 2 ft/s

Hence, velocity of the ball after 1 second is 2 ft/s

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