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3 years ago

Please help!!!! With this problem

Mathematics

1 answer:

aleksley [76]3 years ago

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What is 2/5 of 12930?

Gelneren [198K]

Your answer is 5,172.

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3 years ago

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When traveling to Europe, Bailey converts the temp. given in degrees Celsius to a Fahrenheit temp. by using the expression 9x ÷

lawyer [7]

9(15) / 5 + 32

135 / 5 + 32

27 + 32

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3 years ago

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A. 76° B. 72° C. 70° D. 12°

Crank

Answer:measurement of angle B is

$70 \: \: degrees$

<h3>Answer C is correct</h3>

Step-by-step explanation:

$6x - 2 + 5x + 18 + 2x + 8 = 180 \\ 13x + 24 = 180 \\ 13x = 180 - 24 \\ 13x = 156 \\ \frac{13x}{13} = \frac{156}{13} \\ x = 12 \: \: degrees$

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3 years ago

Determine the x- and y-intercepts of the graph ofx−4y=8Then plot the intercepts to graph the equation.

Over [174]

The x-intercept is the point where the graph cuts the x-axis, and the y-intercept is the point where the graph cuts the y-axis.

The x-axis is the line y = 0 and the y-axis is the line x = 0. To find the intercept between each axis and our graph, we just need to evaluate our function at x = 0 and y = 0.

Calculating the x-intercept, we have

$\begin{gathered} x-4\cdot0=8 \\ x=8 \end{gathered}$

The x-intercept is (8, 0).

Calculating the y-intercept, we have

$\begin{gathered} 0-4y=8 \\ y=-\frac{8}{4} \\ y=-2 \end{gathered}$

The y-intercept is (0, -2).

8 0

1 year ago

Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.

Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

Step 1

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

Step 2

Using the distance formula

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given E(-2,3), F(1,6)

$|EF|=\sqrt{(6-3)^2+(1-(-2))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given F(1,6), G(4,3)

$|FG|=\sqrt{(3-6)^2+(4-1)^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given G(4,3), H(1,0)

$|GH|=\sqrt{(0-3)^2+(1-4)^2}=\sqrt{(-3)^2+(-3)^2}=\sqrt{18}=3\sqrt{2}$

Given E (−2, 3), H (1, 0)

$|EH|=\sqrt{(0-3)^2+(1-(-2))^2}=\sqrt{(-3)^2+(3)^2}=\sqrt{18}=3\sqrt{2}$

Step 3

Segment EF ,E (−2, 3), F (1, 6)

Slope of |EF|= $\frac{6-3}{1+2} =\frac{3}{3}=1$

Segment GH, G (4, 3), H (1, 0)

Slope of |GH| $= \frac{0-3}{1-4} =\frac{-3}{-3}=1$

Step 4

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH| $= \frac{0-3}{1+2} =\frac{-3}{3}=-1$

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| $=\frac{3-6}{4-1} =\frac{-3}{3}=-1$

Step 5

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

Step 6

Segment EF, segment FG, segment GH, and segment EH are congruent.

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

Step 7

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

4 0

3 years ago

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