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kotegsom [21]
3 years ago
9

What would be the best method to use in order to solve the following quadratic equation?

Mathematics
2 answers:
deff fn [24]3 years ago
8 0
Quadratic Formula
a=4
b=29
c=-60

x = -29 +- sq root(841 -4*4*-60) / 2*4
x = -29 +- sq root(841 +960) / 8
x = -29 +- sq root(1,801) / 8
x = [-29 +- <span> <span> <span> 42.4381903478] </span> </span> </span> / 8

x1 = <span> <span> <span> 13.4381903478 </span> </span> </span> / 8
x1 = <span> <span> <span> 1.6797737935 </span> </span> </span>

x2 = [-29 - <span> <span> 42.4381903478] </span> </span> / 8
x2 = <span> <span> <span> -71.4381903478 </span> </span> </span> / 8
x2 = <span> <span> <span> -8.9297737935 </span> </span> </span>







never [62]3 years ago
6 0

Answer:

b) Quadratic Formula

Step-by-step explanation:

The given expression is :

4x^{2} +29x-60=0

We will solve this by using Quadratic Equation Formula.

When the equation is in the form of ax^{2} +bx+c=0 we use the formula:

x1 =\frac{-b+\sqrt{b^{2}-4ac}}{2a} and x2 =\frac{-b-\sqrt{b^{2}-4ac}}{2a}

Here a = 4, b = 29 and c = -60

Putting these in formula we get:

x1 =\frac{-29+\sqrt{29^{2}-4\times4\times(-60)}}{2(4)} and

x2 =\frac{-29-\sqrt{29^{2}-4\times4\times(-60)}}{2(4)}

Solving these we get,

x1=\frac{-29+\sqrt{1801}}{8} and

x2=\frac{-29-\sqrt{1801}}{8}

The final answer are :

x1=1.6797

x2=-8.9297

So, the quadratic formula is used here.

Factorization is not possible as the given equation is not a perfect square.

Taking the Square Root method will also not work here as this method helps when the expression contains only x^{2} term.

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