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mars1129 [50]
3 years ago
9

68 + 43 sorry my partner asked me

Mathematics
2 answers:
Neko [114]3 years ago
7 0
The answer to that is 111
ElenaW [278]3 years ago
4 0
Simple addition. 68 plus 43 is 111.
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A value two standards deviation from the mean is more likely to occur than a value three standard deviations from the mean.
Alexxandr [17]

Answer:

A value two standards deviation from the mean is more likely to occur than a value three standard deviations from the mean.

Step-by-step explanation:

Standard deviation is a quantitative measure of the variability of traits of the subjects in a given population. These traits can range from age, height, weight e.t.c. This deviation is brought about by extreme or abnormal conditions, which is the reason why two deviations is more likely to occur than three deviations.

Moreover, going by the provisions of the empirical rule, If data comes from a population that is approximately symmetrical;

95% of the data will fall within two standard deviations.

99.7% will fall within three standard deviations

Find the attachment below.

Nevertheless, in a symmetrical distribution most of the data values fall around the mean. Two standard deviations is closer to the mean than 3 standard deviations hence more likely to occur.

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4 years ago
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Find the trapezoid.The trapoized has an area of
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Answer: what trapezoid?

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3 years ago
Jim rents an apartment in New York City for $1600 a month. Mike rents his apartment in Boston for 7/8 as much. How much more doe
worty [1.4K]

Answer:

Jim pays 200 more dollars per month than Mike.

Step-by-step explanation:

Jim--> $1600/month

Mike--> 7/8(Jim's rent)

7/8(Jim's rent)

7/8(1600)

= $1400

1600-1400= 200

Jim pays 200 more dollars per month than Mike.

I hope that makes sense!

4 0
4 years ago
A weighted die comes up spots with the following probabilities: Spots 1 2 3 4 5 6 Probability 0.10 0.15 0.20 0.25 0.20 0.10 If t
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Answer:

Probability (A sum of 10)=0.1025

Step-by-step explanation:

\begin{center}\begin{tabular}{ c c c c c c c } Spots & 1 & 2& 3 & 4& 5 & 6 \\ \\Prob & 0.10 & 0.15& 0.20 & 0.25& 0.20 & 0.10     \end{tabular}\end{center}

To find the Probability the sum is 10, we can either have

i. a 4 and a 6

ii. a 5 and a 5

Pr (A AND B) = Pr (A) x Pr(B)

Pr (A OR B) = Pr (A) + Pr(B)

Probability (A sum of 10) = Pr(getting a 4 AND a 6) OR Pr(getting a 5 AND a 5)

=(0.25 x 0.25)+(0.20 x 0.20)

=0.0625+0.04

=0.1025

3 0
3 years ago
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