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2 years ago

mr tonneman buys one 2 pound lobster and 1 pound 4 ounces of shrimp. find the ratio the weight of the lobster to the shrimp

Mathematics

1 answer:

Phantasy [73]2 years ago

5 0

2:1over4 this would be the ratio answer

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X divided by 5 is greater than or equal to 6

posledela

30 Answer:

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2 years ago

I really need help :)

iren2701 [21]

Answer:

Could anyone help me with this problem please?

What is one value that makes the fraction (x^2 + 11x +30)/(4x + 44x^2 + 120x) Undefined?

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2 years ago

The yearbook club is handing out T-shirts to its members. There are 5 blue, 7 green, 9 red, and 4 yellow T-shirts in all. If Jac

Neporo4naja [7]

Answer:

well it's 9/25 or 0.36% or (36%) only

Step-by-step explanation:

So you add all the numbers up it would be 25, divide the numerator by the denominator and get 0.36%, i can't remember if you divide .36 by 100 or not but anyway you get 36%.

But I hope i have helped you in anyway.

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3 years ago

Solve for x: 2x − 2 > 4x + 6.<br> x < −4<br> x > −4<br> x < 4<br> x > 4

igomit [66]

Answer:

The answer is the first choice, x < −4.

Step-by-step explanation:

Let's solve your inequality step-by-step.

2x−2>4x+6

Step 1: Subtract 4x from both sides.

2x−2−4x>4x+6−4x

−2x−2>6

Step 2: Add 2 to both sides.

−2x−2+2>6+2

−2x>8

Step 3: Divide both sides by -2.

x<−4

3 0

3 years ago

Jerry has a miniature model of a boat. He knows that the boat is 3 3/4 inches wide and 5 1/2 inches long. What is the actual len

FromTheMoon [43]

Width of the miniature model = $3\frac{3}{4}$ inches

Length of the miniature model = $5\frac{1}{2}$ inches

The actual width of the boat = 15 feet

Let us find the actual length of the boat.

Write it in a proportion form.

width of model : length of model : : width of actual : length of actual

$$\Rightarrow 3\frac{3}{4}:5\frac{1}{2}::15:x$

$$\Rightarrow\frac{15}{4}:\frac{11}{2}::15:x$

$$\Rightarrow\frac{\frac{15}{4}}{\frac{11}{2}} =\frac{15}{x}$

Do cross multiplication.

$$\Rightarrow{\frac{15}{4}x =15\times\frac{11}{2}$

$$\Rightarrow{\frac{15}{4}x =\frac{165}{2}$

$$\Rightarrow x =\frac{165}{2}\times{\frac{4}{15}$

⇒ x = 22

Hence the actual length of the boat is 22 feet.

6 0

3 years ago