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svlad2 [7]
3 years ago
7

A triangle lies entirely in Quadrant 1. In which quadrant will the triangle lie after each rotation about (0, 0)?

Mathematics
2 answers:
ladessa [460]3 years ago
7 0
Hello there! :D (again)

Explanation:
Well, (0,0) its accesible only in quadrant 1 and 2, because if not it would be (-0,-0) or (-0,0), or even (0,-0)

So, if we think about it, we already have (0,0) in Quadrant 1,so for it to give us the same pair as positive, it would need to be in Quadrant 2.

Answer:
Quadrant 2.
(if you have any questions please ask me)

-Ari.
tester [92]3 years ago
6 0
Well, if the the triangle is rotated clockwise it will lie in quadrant 4. if it is rotated anticlockwise it will lie on quadrant 2
hope this helps
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Consider a binomial distribution of 200 trials with expected value 80 and standard deviation of about 6.9. Use the criterion tha
mote1985 [20]

Answer:

The correct answer is option 'a' : 120 is more than 2.5 standard deviations above the expected value.

Step-by-step explanation:

For an exponential distribution we have

The expected value μ = 80

No of trails n = 200

Thus we have

p=\frac{80}{200}=0.4

The deviation is related to expected value and probability as

\sigma =\sqrt{np(1-p)}\\\\\therefore \sigma =\sqrt{200\cdot 0.4\cdot (1-0.4)}=6.9

Thus the values between the given deviation is

x_{1}=80-2.5\times 6.9=62.75\\\\x_{2}=80+6.9\times 2.5=97.25

Now since 120 successes are out of the range of [62.75,97.25] thus 120 is more than the expected value.

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3 years ago
Lacy pays $15 for each hour of golf lessons and $10 for equipment rental. If the lesson is more than 3 hours long, she only pays
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Answer:

60

Step-by-step explanation:

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4 0
3 years ago
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Find all the zeros of the equation
lapo4ka [179]

Divide both sides by -3, and replace x^2 with y. Then

-3x^4+27x^2+1200=0\iff y^2-9y-400=0

Factorize the quadratic in y to get

y^2-9y-400=(y+16)(y-25)=0\implies y=-16,y=25

which in turn means

x^2=-16,x^2=25

But x^2\ge0 for all real x, so we can ignore the first solution. This leaves us with

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If we allow for any complex solution, then we can continue with the solution we ignored:

x^2=-16\implies x=\pm\sqrt{-16}=\pm i\sqrt{16}=\pm4i

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4 years ago
B(n) = -1 (2)^n-1 What is the 5th term in the sequence?
bija089 [108]

Answer:

<h2>The answer is - 16</h2>

Step-by-step explanation:

<h3>b(n) =  - 1 ({2})^{n - 1}</h3>

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From the question since we are finding the 5th term

n = 5

Substitute the value into the above formula and solve

We have

b(5) =  -  1({2})^{5 - 1}  \\  =  - 2 ^{4}

We have the final answer as

<h3>- 16</h3>

Hope this helps you

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Answer:

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