
Substituting this into the other ODE gives

Since  , it follows that
, it follows that  . The ODE in
. The ODE in  has characteristic equation
 has characteristic equation

with roots  , admitting the characteristic solution
, admitting the characteristic solution

From the initial conditions we get



So we have

Take the derivative and multiply it by -1/4 to get the solution for  :
:

 
        
             
        
        
        
where's the storyy sisssssss
 
        
             
        
        
        
It is C, if it falls 14 ft. and it travels back up 7 ft. and then falls another 7 ft, and stops at the ground now you add it all up 14+7+7=28. hope that helps you.
        
                    
             
        
        
        
Answer:
The dimensions of the yard are W=20ft and L=40ft.
Step-by-step explanation:
Let be:
W: width of the yard.
L:length.
Now, we can write the equation of that relates length and width:
 (Equation #1)
 (Equation #1)
The area of the yard can be expressed as (using equation #1 into #2):
 (Equation #2)
 (Equation #2)
Since the Area of the yard is  , then equation #2 turns into:
, then equation #2 turns into:

Now, we rearrange this equation:  

We can divide the equation by 5 :

We need to find the solution for this quadratic. Let's find the factors of 160 that multiplied yields -160 and added yields -12. Let's choose -20 and 8, since  and
 and  . The equation factorised looks like this:
. The equation factorised looks like this:

Therefore the possible solutions are W=20 and W=-8. We discard W=-8 since width must be a positive number. To find the length, we substitute the value of W in equation #1:

Therefore, the dimensions of the yard are W=20ft and L=40ft.