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3 years ago

Can someone please help me?? I don’t understand what the order is? And or the symmetry

Mathematics

1 answer:

Vika [28.1K]3 years ago

3 0

It is probably a rectangle so u see the answer would make s eve but in your mind does it

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Interoperate your solution in the context of the problem.<br> f(10)=1.75r+9

iVinArrow [24]

Answer:

Simplifying

f(r) = 5 + 1.75r

Multiply f * r

fr = 5 + 1.75r

Solving

fr = 5 + 1.75r

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'r'.

f = 5r-1 + 1.75

Simplifying

f = 5r-1 + 1.75

Reorder the terms:

f = 1.75 + 5r-1

Step-by-step explanation:

tada i think

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3 years ago

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Cam has 32 dollars. How many roses can he afford to buy?

Vlad [161]

Answer:

8 roses

Step-by-step explanation:

roses cost about 4 dollars, and 8 times 4=32

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3 years ago

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IRISSAK [1]

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3 years ago

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Write these numbers in order from least to greatest. ( 3-3/10), (3.1) , (3-1/4)

Orlov [11]

Our three numbers are...

3 3/10 = 3.3

3.1

3 1/4 = 3.25

So, if we order those from least to greatest, we have...

3.1, 3.25, 3.3

which, in the forms given, is...

3.1, 3-1/4, 3-3/10

7 0

3 years ago

Dilate a triangle with vertices (0,0), (0,2) and (2,0) using the scale factor k=3. What is the value of the ratio (new to origin

seropon [69]

Answer:

Part a) The ratio of the perimeters is $3$

Part b) The ratio of the areas is $9$

Step-by-step explanation:

Part A) What is the value of the ratio (new to original) of the perimeters?

we know that

If two figures are similar, then the ratio of its perimeters is equal to the scale factor

Let

z-----> the scale factor

x-----> the perimeter of the new triangle

y-----> the perimeter of the original triangle

$z=\frac{x}{y}$

we have

$z=3$

substitute

$\frac{x}{y}=3$

Part B) What is the value of the ratio (new to original) of the areas?

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z-----> the scale factor

x-----> the area of the new triangle

y-----> the area of the original triangle

$z^{2}=\frac{x}{y}$

we have

$z=3$

substitute

$\frac{x}{y}=3^{2}$

$\frac{x}{y}=9}$

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3 years ago