Given:
The given digits are 1,2,3,4,5, and 6.
To find:
The number of 5-digit even numbers that can be formed by using the given digits (if repetition is allowed).
Solution:
To form an even number, we need multiples of 2 at ones place.
In the given digits 2,4,6 are even number. So, the possible ways for the ones place is 3.
We have six given digits and repetition is allowed. So, the number of possible ways for each of the remaining four places is 6.
Total number of ways to form a 5 digit even number is:


Therefore, total 3888 five-digit even numbers can be formed by using the given digits if repetition is allowed.
Answer:
60
Step-by-step explanation:
In the function, the growth factor is "a", the base of the exponent. When the exponent is increased by 1, the value is multiplied by "a".
f(7) = a·f(6) = 4·15
f(7) = 60
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As you know, the exponent signifies repeated multiplication. So, an increase of 1 in the exponent means the base is part of the product one more time:
a^6 = a·a·a·a·a·a
a^7 = a·a·a·a·a·a·a = a·(a^6)
2p*p= 2p^2 because when you multiply p by p it squares it, then you keep the 2 in front of it