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Step2247 [10]
3 years ago
14

Which expression is equivalent to (7x - 5)-(3x - 2)?

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
8 0

(7x - 5)-(3x - 2)

Pretend that there is a -1 in front of the second bracket

(7x-5)-1(3x-2)

Multiply the second bracket by -1

7x-5-3x+2

7x-3x-5+2

4x-3

Answer: D. 4x - 3

Tcecarenko [31]3 years ago
6 0

Answer:

option D

Step-by-step explanation:

(7x - 5)-(3x - 2)

7x-5-3x+2

4x-3

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The line AB has the midpoint of (2,5) A has coordinates (1,7) find the coordinates of B
Pavel [41]

Answer:

Point B is at (3,3)

Step-by-step explanation:

the mid point is (2,5) and A is at (1,7)

first find the slope:

y1 - y2/x1 - x2

7 - 5/1 - 2

2/-1

-2/1

then go down 2 units and right 1 unit from (2,5):

(2 + 1, 5 - 2) => (3,3)

6 0
3 years ago
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3 years ago
Mr. Castillo earns 270,920.64 a year. What is his monthly salary?
lozanna [386]

We need to divide for this. Since there are 12 months in a year, we divide his yearly salary by 12.

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So, Mr.Castillo's monthly salary is $22,576.72.

8 0
3 years ago
Ten years ago 53% of American families owned stocks or stock funds. Sample data collected by the Investment Company Institute in
Alborosie

Answer:

a) Null hypothesis:p\geq 0.53  

Alternative hypothesis:p < 0.53  

b) z=\frac{0.46 -0.53}{\sqrt{\frac{0.53(1-0.53)}{300}}}=-2.429  

p_v =P(Z

c) So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of American families owning stocks or stock funds is significantly less than 0.53 .  

Step-by-step explanation:

Data given and notation

n=300 represent the random sample taken

\hat p=0.46 estimated proportion of American families owning stocks or stock funds

p_o=0.53 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

Part a

We need to conduct a hypothesis in order to test the claim that proportion is less than 0.53 or 53%.:  

Null hypothesis:p\geq 0.53  

Alternative hypothesis:p < 0.53  

Part b

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.46 -0.53}{\sqrt{\frac{0.53(1-0.53)}{300}}}=-2.429  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z

Part c  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of American families owning stocks or stock funds is significantly less than 0.53 .  

7 0
3 years ago
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