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muminat
3 years ago
11

Please help me with my problem. I would really appreciate it

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0
I"d say the answer is A im happy to help whenever have a good day!
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Gina and rhonda work for different real estate agencies gina earns a monthly salary of $5,000 plus 6% commission on her salary r
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Each must sell 35,678 dollars each year not counting commision to add 6 percent of that. 
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3 years ago
Keith sold half of his comic books and then bought nine
Nadusha1986 [10]

Answer:

22 comic books.

Step-by-step explanation:

(20 - 9) * 2 First subtract 9 from 20

11 * 2 Multiply 11 by 2

22 is the product

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Please help me don’t skip! I need help with 3 and 4
densk [106]

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Step-by-step explanation:

8 0
3 years ago
Simplify the following expression.
erica [24]

Answer:

B)  53x + 74

Step-by-step explanation:

(59x + 64) - (6x - 10) = 59x + 64 - 6x + 10

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3 0
3 years ago
A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee
katrin [286]

Answer: A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

^nC_r=\dfrac{n!}{(n-r)!r!}

Given : Total multiple-choice questions  = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

No. of ways to answer 6 multiple-choice questions

= ^9C_6=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!3!}=84

No. of ways to answer 4 open-ended problems

= ^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6\times5\times4!}{4!2!}=15

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

= 84\times15=1260

Hence, the correct answer is option A) 1260

5 0
3 years ago
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