Question

The graph of which function will have a maximum and a y-intercept of 4? f(x) = 4x2 + 6x – 1 f(x) = –4x2 + 8x + 5 f(x) = –x2 + 2x + 4 f(x) = x2 + 4x – 4

Answer 1

Answer:

It is f(x) = -x^2 + 2x + 4.

Step-by-step explanation:

As it has a maximum the coefficents of x^2 will be negative.

f(x) = -x^2 + 2x + 4

The y-intercept occurs when x = 0 so

y-intercept = 0 + 0 + 4 = 4.

-

Answer 2

ANSWER

$f(x) = - {x}^{2} + 2x + 4$

EXPLANATION

The graph of the function that will have a maximum and a y-intercept of 4 is

$f(x) = - {x}^{2} + 2x + 4$

To check for the y-intercept, we put x=0 into the function.

$f(0) = - {0}^{2} + 2(0)+ 4$

This implies that,

$f(0) = 4$

We can see that the coefficient of the quadratic term is -1.

Since the coefficient of the quadratic term is less than zero, the graph will have a maximum point.