probably this would help.
to solve this system I first multiplied the second equation by 2 to make the x coefficient equal. then I subtracted equation two from equation one. this eleminated the x. solving for y gave me y=0. then I put 0 back in the original equation and that gave me x=-4.
Find a number of right that is a multiple of 10.
There are such lines:
21 wrong and 70 right: this is 70/21 = 10/3 = 10:3
23 wrong and 20 right
The correct answer is the third choice.
Answer: 95040
Step-by-step explanation:
It is important to note that selection and arrangement are two different things in permutation and combination study. In the scenario above, we have 12 books, out of which 5 is to be arranged on a shelf. The answer prescribed by 12C5 which gives 792, only solves the selection process of choosing 5 books from a total of 12. Every 5 books picked will also have to be arranged on the shelf which is solved as n!(number of ways of arranging n different objects)
Hence, to arrange 5 books from a total of 12 books on a book shelf is
nCr * r!
12C5 * 5!
792 * 120
= 95040
Answer:
p=62 q= 35
Step-by-step explanation:
<h2>hope this helps</h2>
<h2>please rate and mark brainliest</h2>
