First get y by its self , then graph , find intersection point and plug in x and y to both equations, see if it makes sense , then the solution must be you intersection point
Answer:
Two equiangular decagons are sometimes congruent.
F(x)=3x2-11
f(5)=6-11
5f=-5
5f/5=-5/5
f=-1
Since there are four suits, with each having a 4 and 5, we have 2+2+2+2=2*4=8