If you would like to solve - 3 * a^2 - b^3 + 3 * c^2 - 2 * b^3, if a = 2, b = -1, c = 3, you can calculate this using the following steps:
a = 2, b = -1, c = 3
- 3 * a^2 - b^3 + 3 * c^2 - 2 * b^3 = - 3 * 2^2 - (-1)^3 + 3 * 3^2 - 2 * (-1)^3 = - 3 * 4 - (-1) + 3 * 9 - 2 * (-1) = - 12 + 1 + 27 + 2 = 18
The correct result would be 18.
3M^2 + 11MN + 6N^2 = 3M^2 + 2MN + 9MN + 6N^2
= M(3M + 2N) + 3N(3M + 2N) = (3M + 2N)(M + 3N)
Answer: 3M^2 + 11MN + 6N^2 = (3M + 2N)(M + 3N)
Answer:
Option D - x = 3 3/5
Step-by-step explanation:
Lets make the left side into an improper fraction :
2 2/5 = 12/5
Now let's make both fraction into equivalent ones but with the same denominator :
2/3 = 10/15
12/5 = 36/15
Now we substitute the equivalent values back into the equation :
10/15 × x = 36/15
Now we multiply both sides by 15 to remove the denominators:
10 × x = 36
Now we divide both sides by 10 and simplify :
x = 36/10
x = 18/5
x = 3 3/5
So our answer will be Option D
Hope this helped and brainliest please
