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3 years ago

Need help for study guide...REALLY APPRICIATED!!!

Mathematics

1 answer:

atroni [7]3 years ago

7 0

4) 18=x+3x+2
-2 -2
14= 4x
x=7

5) 12h-6=138
+6. +6
12h=144
h=12

6) -3x-4x+16=2
-16. -16
-7x=-14
x=+2

7) -5(7x+1)=36
-35x-5=36
+5. +5
-35x=41
x=-1.17142857142

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PLEASE HELP ME ?!!!!!

cluponka [151]

Answer:

b & c for sure

Step-by-step explanation:

............

8 0

3 years ago

A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch

ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

$P$ = a person passes the security system

$H$ = a person is a security hazard

Given:

$P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01$

Then,

$P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\$

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: $P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The value of P (P) is:

$P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412$

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

$P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1$

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

7 0

3 years ago

Express the statement as an inequality.

Lady_Fox [76]

The expression of the inequality word problems for each question is; As expressed below

<h3>How to express inequalities?</h3>

A) x is negative. This can be expressed as;

x < 0

B) y is non-negative. This can be expressed as;

y > 0

C) q is less than or equal to is expressed as; q ≤

D) d is between 2 and 1 is expressed as 1 < d < 2

E) t is not less than 5 is t ≥ 5

F) The negative of z is not greater than 3 is expressed as;

−z ≤ 3

G) The quotient of p and q is at most 6 is expressed as; p/q ≤ 6

H) The reciprocal of w is at least 9 is 1/w ≥ 9.

Read more about Inequalities at; brainly.com/question/24372553

#SPJ1

8 0

2 years ago

Janice is training for a 5K. She predicted she would spend 90 minutes running this week. She actually ran for a total of 120 min

Levart [38]

I agree with the other person that this is 25% error

4 0

3 years ago

Read 2 more answers

If triangle ABC is similar to triangle DEC, find the values of x and y.

Mumz [18]

The values are x=8 and y=35, if the given ΔABC and ΔDEC are equal, it is obtained by Pythagoras theorem.

Step-by-step explanation:

The given are,

From ΔABC,

AB= 6

BC= 10

AC = x

From ΔDEC,

CD= 28

DE= 21

CE = y

Step:1

Pythagoras theorem from ΔABC,

$BC^{2}=AB^{2} + AC^{2}$ ...............(1)

Substitute the values,

$10^{2}$ = $6^{2}$ + $AC^{2}$

100 = 36 + $AC^{2}$

$AC^{2}$ = 100 - 36

= 64

AC = $\sqrt{64}$

AC = 8

AC = x = 8

Step:2

Pythagoras theorem for ΔDEC,

$CE^{2} = CD^{2} + DE^{2}$ ................(2)

From the values,

$CE^{2}$ = $28^{2}$ + $21^{2}$

$CE^{2}$ = 784 + 441

= 1225

CE = $\sqrt{1225}$

CE = 35

CE = y = 35

Result:

The values are x=8 and y=35, if the given ΔABC and ΔDEC are equal.

5 0

3 years ago