Groundwater is the water found beneath the earth's surface in spaces in soil, in cracks and rocks. These spaces are called aquifers. Groundwater serves many purposes where most of it is used in irrigation purposes. In the year 2005, 68 percent, most of the groundwater withdrawals, were used for irrigation, 19 percent was for public supply and the remaining 13 percent was used for other applications in industries.
Answer:
C. +23.1 kJ/mol
Explanation:
the formula to use to calculate the energy requirement in kJ/mol to transport a proton across the mitochondrial inner membrane in plant cells is:
ΔGt = RTIn
+ ZFΔV
let's list the values of the data we are being given in the question to make it easier when solving it.
Z= 1
F= 96500C (faraday's constant)
ΔV= 160mV = 0.160V
R= 8.314( constant)
T= 15ºC ( converting our degree Celsius into kelvin, we will have 273.15k+ 15 = 288.15K)
∴ T= 288.15K
Putting it all together in the formula, we have:
ΔGt = 8.314 × 288.15 × 2.303 log
+ 1 × 96500 × 0.160
ΔGt = 5517.25
+15440
ΔGt = 5517.25
+15440
Given that the pH differential gradient across the membrane is 1.4pH units. It implies that;
ΔGt = 5517.25 × 1.4 + 15440
= 7724.15 +15440
= 23164.15 Joules/moles
= +23.1 KJ/mole
3(x+2)=5x-4
Add two and x then multiply by three, set equal to five times x minus four
Answer:
the answer is plant growth