Answer:
(-8/7 ; 5/7)
Step-by-step explanation:
5t + 1/2s = 3 - - - (1)
3t - 6s = 9 - - - - - (2)
Multiply (1) by 12 and (2) by 1
Add the result to eliminate s
60t + 6s = 36
3t - 6s = 9
____________
63t = 45
t = 45 / 63
t = 5/7
Put t = 5/7 in either (1) or (2) to obtain the value of s
3(5/7) - 6s = 9
15/7 - 6s = 9
-6s = 9 - 15/7
-6s = (63 - 15)/7
-6s = 48/7
s = 48/7 * - 1/6
s = - 8/7
Answer:
16 × 2 × 2
Step-by-step explanation:
64 = 2 × 2 × 2 × 2 × 2 × 2
=> 16 × 2 × 2
If ages are normally distributed then using a significance level of 0.05 , we can claim that the population mean is greater than 24.
Given sample mean of 25 years , sample size of 16 ,standard deviation of 2 years.
We have to find whether the population average is greater than 24.
We have to use t test because n is less than 30. It is right tailed.
We have to first form Hypothesis.
:μ>24,
:μ<24.
t=X-μ/S/
t critical at 5% significance level and degree of freedom=15 (16-1)=1.7531
t=24-25/2/
=-1/0.5
=-2
Because 1.7531 is greater than -2 so we will accept the null hypothesis.
Hence we can say that the average of population is greater than 24.
Learn more about t test at brainly.com/question/6589776
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Answer:
No probllem linked
Step-by-step explanation:
4.05 - 3.24 = 0.81
(0.81 / 3.24)*100 = 25%