Question

What is the value of the rational expression x^2-2x-3/4x^2-12 when x = 3?

Answer 1

Answer:

b

Step-by-step explanation:

Given

$\frac{x^2-2x-3}{4x^2-12}$

Substitute x = 3 into the expression

= $\frac{3^2-2(3)-3}{4(3)^2-12}$

= $\frac{9-6-3}{36-12}$

= $\frac{0}{24}$ = 0 → b