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Ilya [14]
3 years ago
11

Alles Company uses a job costing system that applies factory overhead on the basis of direct labor dollars. No job was in proces

s on February 1. During the month of February, the company worked on these three jobs:
Job Number
B10 C44 G15
Direct labor ($6/hour) $ 35,000 ? $ 10,500
Direct materials 43,000 62,000 ?
Overhead applied ? 22,000 5,250


During the month, the company completed and transferred Job B10 to the Finished Goods Inventory. Jobs C44 and G15 were not completed and remain in Work-in-Process at the cost of $158,650 at the end of the month. Actual factory overhead costs during the month totaled $40,000.


Required:

1. What is the predetermined factory overhead rate?

2. Compute the amount of underapplied or overapplied overhead for February.

Questions to answers are below:
Question 1:
What is the predetermined factory overhead rate? (round answer to 2 decimal places.)
Overhead rate____?____ per direct labor dollar.

Question 2:
Compute the amount of underapplied or overapplied overhead for February. (Do not round intermediate calculations.)
Overapplied overhead ____?_____.
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
5 0

Answer:

The labor force participation rate and the employment-population ratio were both unchanged over the month, at 61.5 percent and 57.4 percent, respectively. These measures are up from their recent April lows but are lower than in February by 1.8 percentage points and 3.7 percentage points, respectively.Jan 8, 2021

www.bls.gov › pdf › empsitPDF

Unemployment - Bureau of Labor Statistics

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sleet_krkn [62]

Answer:

(-4,5)

Step-by-step explanation:

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Is 1.2 less than or higher than 1.5
Olenka [21]

1.2 is less than 1.5

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sveticcg [70]

Answer:

Option C is correct.

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Step-by-step explanation:

Given the equation: 3x^2+10 = 4x

We can write this equation as:

3x^2-4x + 10 =0

A quadratic equation is in the form of ax^2+bx+c =0      ......[1] where a,b ,c are the coefficient and x is the variable,

the solution of the equation is given by;

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On comparing given equation with equation [1] we get;

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So, the solution of the given equation is given by;

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or

x =  \frac{4\pm\sqrt{(16-120}}{6} = \frac{4\pm\sqrt{(-104)}}{6} = \frac{4\pm\sqrt{(-4 \times 26)}}{6}

or

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Simplify:

x =\frac{2\pm i\sqrt{26}}{3}

therefore, the roots of the given equation are; x =\frac{2\pm i\sqrt{26}}{3}

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Answer:

3

Step-by-step explanation:

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