Answer:
96.4% of people have an IQ score between 69 and 132
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:
What percentage of people have an IQ score between 69 and 132, to the nearest tenth?
The proportion is the pvalue of Z when X = 142 subtracted by the pvalue of Z when X = 69. The percentage is the proportion multiplied by 100. So
X = 132
has a pvalue of 0.983
X = 69
has a pvalue of 0.019
0.983 - 0.019 = 0.964
0.964*100 = 96.4%
96.4% of people have an IQ score between 69 and 132
Explanation:
We will try to simplify the given expression into terms of ab and then substitute with ab = x as follows:
2a³b + a²b + ab
a² (2ab + ab) + ab
a² (3ab) + ab
a² (3x) + x
Since ab = x, therefore, a = x/b
Substitute with this in the above expression to get:
(x/b)²(3x) + x
+ x
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Answer:
x=4
Step-by-step explanation:
3(x+2) = 2(x+5)
Distribute
3x+6 = 2x+10
Subtract 2x from each side
3x-2x+6 = 2x-2x+10
x +6 = 10
Subtract 6 from each side
x+6-6 = 10-6
x = 4
Answer:
i dont know i think it is 11?!? srry if im wrong
Step-by-step explanation:
Answer:
he simplified expression is 243 . Explanation: You can rewrite the fractional exponent as roots and powers, like this: =xmn=n√xmor(n√x)m.
Step-by-step explanation: