If the question is to find the slope-intercept form of both lines, here's the answer:
Both lines pass through the point (-3,-4), so we can use these coordinates in both equations. The slope-intercept form is represented by y=mx+b, with m the slope, b the intersection of the line with Y'Y for x=0, y and x the coordinates of a point.
Let's first apply all these for the first line, with a slope of 4.
y = mx + b
y=-3; x=-4; m=4. All we need to do is find b.
-3 = 4(-4) + b
-3 = -16 + b
b=13
So the equation of the first line is y= 4x + 13.
Now, we'll do the same thing but for the second line:
y=-3; x=-4; m=-1/4, and we need to find b.
-3 = (-1/4)(-4) + b
-3 = 1 + b
b= -4
So the equation of the second line is y=(-1/4)x - 4
Hope this Helps! :)
Answer:
(15,16)
Step-by-step explanation:
C=halfway between A to B
A to B on the x axis goes across by 24
24/2 =12
3+12=15
A to B on the y axis goes up by 28
28/2 = 14
2+14=16
(15,16)
Use the GCF of the terms to write the expression as the product of two factors with integer coefficients.
-2x3 - 4x2 + 4x
Answer:
2
Step-by-step explanation:
So firstly, <u>the factor (4n - 5) cannot be further factored, so we will be focusing on 2n² + 5n + 3.</u>
So for this, we will be factoring by grouping. Firstly, what two terms have a product of 6n² and a sum of 5n? That would be 2n and 3n. Replace 5n with 2n + 3n:
Next, factor 2n² + 2n and 3n + 3 separately. Make sure that they have the same quantity on the inside of the parentheses:
Now we can rewrite this expression as<u> 
, which is your final answer.</u>
